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Ugo [173]
3 years ago
12

Do hot things, like water or magma, always rise?

Chemistry
1 answer:
Olegator [25]3 years ago
8 0

Answer:

Explanation:

No not always but it is more likely they will

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Calcum chloride contains only calcum and chloride What is the fomula for this compound? fou need the Peodie Table for thia quest
mafiozo [28]

Answer:

CaCl_2

Explanation:

Calcium is the element of the group 2 and period 4 which means that the valence electronic configuration is [Ar]4s^2.

Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is [Ne]3s^23p^5.

Thus, calcium losses 2 electrons to 2 atoms of chlorine and these 2 atoms of chlorine accepts each electron to form ionic bond. This is done in order that the octet of the atoms are complete and they become stable.

Ca         Cl

2            1

Cross multiplying the valency, We get, CaCl_2

Thus, the formula of calcium chloride is CaCl_2.

3 0
3 years ago
Does an electric iron may have a lower wattage than a LED lightbulb
grin007 [14]

Answer:

Below:

Explanation:

An iron will use 800 to 2000 watts, with an average iron using 1100 watts when heated on high.

8 0
3 years ago
The energy produced in the stars results from
faust18 [17]

Answer:

Explanation:

Hydrogen fusion (nuclear fusion of four protons to form a helium-4 nucleus) is the dominant process that generates energy in the cores of main-sequence stars. It is also called "hydrogen burning", which should not be confused with the chemical combustion of hydrogen in an oxidizing atmosphere.

3 0
3 years ago
What's the answer to this question?
Lena [83]
The answer is B- 124 degrees
4 0
3 years ago
Read 2 more answers
The normal boiling point of a substance is defined to be the temperature at which the liquid phase of the substance is in equili
boyakko [2]

Answer:

ΔSv = 0.1075 KJ/mol.K

Explanation:

Binary solution:

∴ a: solvent

∴ b: solute

in equilibrium:

  • μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)

⇒ Ln (1 - Xb) = ΔG/RT

∴ ΔG = ΔHv - TΔSv

⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R

∴ Xb → 0:

⇒ Ln(1) = ΔHv/RT - ΔSv/R

∴ T = T*b....normal boiling point

⇒ 0 = ΔHv/RT*b - ΔSv/R

⇒ ΔSv = (R)(ΔHv/RT*b)

⇒ ΔSv = ΔHv/T*b

∴ T*b = 80°C ≅ 353 K

⇒ ΔSv = (38 KJ/mol)/(353 K)

⇒ ΔSv = 0.1075 KJ/mol.K

5 0
3 years ago
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