Answer:
is the value of the equilibrium constant for this reaction at 756 K.
Explanation:
Equilibrium concentration of 
![[COCl_2]=7.40\times 10^{-4} M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D7.40%5Ctimes%2010%5E%7B-4%7D%20M)
Equilibrium concentration of 
![[CO]=3.76\times 10^{-2} M](https://tex.z-dn.net/?f=%5BCO%5D%3D3.76%5Ctimes%2010%5E%7B-2%7D%20M)
Equilibrium concentration of 
![[Cl_2]=1.78\times 10^{-4} M](https://tex.z-dn.net/?f=%5BCl_2%5D%3D1.78%5Ctimes%2010%5E%7B-4%7D%20M)
The expression of an equilibrium constant can be written as;
![K_c=\frac{[CO][Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
is the value of the equilibrium constant for this reaction at 756 K.
For your first question, that equation only works if your situation is occurring at a constant temperature. Your original question is such a situation - everything occurs at 298.15 K. Therefore, you can use this value in the equation to calculate work.
For your second question, Charles' Law describes how the volume of gas changes as you heat or cool it, PROVIDED PRESSURE AND MOLES OF GAS REMAIN CONSTANT THE WHOLE TIME. In your original question above, temperature stays constant while volume changes. However, what they don't tell you is that this necessarily requires a change in either pressure or moles of gas. Because the question works with the same sample the of gas the whole time (i.e. moles are constant), it is pressure that is changing (and this change will occur according to Boyle's Law, since temperature and moles are held constant).
Hope that clarifies things!
Answer:
Its Convention Current Waves i think
