Answer: The body produce NADPH a reducing equivalents as antioxidants.
Explanation:
During the pentose phosphate pathway reducing equivalents like NADPH is produced which help to prevent oxidative stress. It reduces glutathione via glutathione reductase which converts reactive H2O2 to H2O by glutathione peroxidase.
Because group 1a and 2a are most reactive due to their least number of electrons in their outmost shell compared to group 8a(18)
When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.
The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.
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