The grams of carbon dioxide that are in 35.6 liters of Co2 is calculates as below
calculate the number of moles of CO2
At STP 1 mole = 22.4 L
what about 35.6 liters
= 1mole x 35.6 liters/ 22.4 liters = 1.589 moles
mass of CO2 = moles x molar mass of CO2
= 1.589 mol x 44 g/mol = 69.92 grams
HA ⇄ H⁺ + A⁻
so:
![\frac{[H^+][A^-]}{[HA]} = 1.5 x 10^{-5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D%20%3D%201.5%20x%2010%5E%7B-5%7D%20%20)
and now:

= 1.5 x 10⁻⁵
x is considered very small compared to 0.15
x² = 2.25 x 10⁻⁶
x = 1.5 x 10⁻³
So [H⁺] = 1.5 x 10⁻³
pH = - log [H⁺] = - log (1.5 x 10⁻³) = 2.83
Answer:
1st = saturated
Explanation:
Bro first ka answer saturated he