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kykrilka [37]
3 years ago
5

which of the following choices defined energy in a scientific terms look for the definition of energy

Chemistry
1 answer:
Sati [7]3 years ago
7 0
The answer is the last one .... The ability to do work and cause change

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The value of Henry's law constant for oxygen in water at 242C is 1.66 x 1 ox M/torr. b. c. Calculate the solubility of oxygen in
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25ca an the oxygen gas is 2 atom ur mum
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3 years ago
Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at con
arsen [322]

Answer:

a)  T_b=590.775k

b)  W_t=1.08*10^4J

d)  Q=3.778*10^4J

d)  \triangle V=4.058*10^4J

Explanation:

From the question we are told that:

Moles of N2 n=2.50

Atmospheric pressure P=100atm

Temperature t=20 \textdegree C

                      t = 20+273

                     t = 293k

Initial heat Q=1.36 * 10^4 J

a)

Generally the equation for change in temperature is mathematically given by

\triangle T=\frac{Q}{N*C_v}

  Where

  C_v=Heat\ Capacity \approx 20.76 J/mol/K

T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }

T_b-293k=297.775

T_b=590.775k

b)

Generally the equation for ideal gas is mathematically given by

 PV=nRT

For v double

 T_c=2*590.775k

 T_c=1181.55k

Therefore

PV=Wbc

Wbc=(2.20)(8.314)(1181_590.778)

Wbc=10805.7J

Total Work-done W_t

W_t=Wab+Wbc

W_t=0+1.08*10^4

W_t=1.08*10^4J

c)

Generally the equation for amount of heat added is mathematically given by

Q=nC_p\triangle T

Q=2.20*2907*(1181.55-590.775)\\

Q=3.778*10^4J

d)

Generally the equation for change in internal energy of the gas is mathematically given by

\triangle V=nC_v \triangle T

\triangle V=2.20*20.76*(1181.55-293)k

\triangle V=4.058*10^4J

3 0
2 years ago
Which components can be found in both comparative and experimental investigations, but are never found in descriptive investigat
Reptile [31]

Answer:

HYPOTHESIS, VARIABLES, AND CONTROL GROUP

Explanation:

YOUR WELCOME :)

6 0
3 years ago
Read 2 more answers
Calculate the percent composition for each element in each of the following compounds.
jek_recluse [69]
The answer is c because the calculations for the elements have to connect with the compounds
6 0
3 years ago
A student measures the mass of a 10m^3 block of gold to be 500 kg what is the density of the gold
Anuta_ua [19.1K]

Answer:

d = 50 kg/m³

Explanation:

density = \frac{mass}{volume}

mass = 500 kg

volume = 10m³

\frac{500}{10} = 50

d = 50 kg/m³

8 0
3 years ago
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