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3 years ago

which of the following choices defined energy in a scientific terms look for the definition of energy

Chemistry

1 answer:

Sati [7]3 years ago

7 0

The answer is the last one .... The ability to do work and cause change

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sashaice [31]

I think it's DNA forms a double helix and RNA consists a single strand.
I may be wrong...

3 0

3 years ago

Read 2 more answers

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔

Vilka [71]

Answer : The correct option is, (C) 1.1

Solution : Given,

Initial moles of $N_2O_4$ = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

The given equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initially c 0

At equilibrium $(c-c\alpha)$ $2c\alpha$

The expression of $K_c$ will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

where,

$\alpha$ = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

$K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}$

$K_c=1.066\aprrox 1.1$

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0

3 years ago

If I have 3 liters of solute, and 4 liters of solvent how many liters in solution do I have?

yaroslaw [1]

Answer:

seven litres i

i.e three litres plus four litres

5 0

3 years ago

The maximum number of electrons in each type of sublevel (s, p, d, and f, respectively

Soloha48 [4]

S = 2
p = 6
d =10
f = 14

6 0

3 years ago

What is the average kinetic energy of 1 mole of a gas that is at 100 degrees Celsius?

Paha777 [63]

The average kinetic energy of an ideal gas is calculated as

KE_avg = 3/2 kT

where T is the temperature in Kelvin and k=R/N_A; R is the universal gas constant and N_A is the number of moles.

Thus, upon substitution we get

KE_avg = 3/2(8.314/1)(100+273)
KE_avg = 3/2(8.314)(373)
KE_avg = 4651.683

The average kinetic energy of 1 mole of a gas at 100 degree Celsius is 4651.683 J.

3 0

3 years ago