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Roman55 [17]
2 years ago
11

I need friends and I’m in middle school :)

Chemistry
1 answer:
kakasveta [241]2 years ago
5 0

Answer:

Ok?

Explanation:

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Name each of the following species for the following acid-base reactions. (The equilibrium lies to the right in each case, i.e.,
DaniilM [7]

Answer: a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.

The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base

For the given chemical equation:

a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

.

3 0
2 years ago
A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10
Alex17521 [72]

Answer:

Mass of P4O6=103.4

            P4O10=133.48

Explanation:

Balanced reaction is:

8P +8O_{2}  ⇒P_{4} O_{6} +P_{4} O_{10}

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P=\frac{117.9}{31} =3.80

Moles of O_{2} =\frac{117.9}{31} =3.80

No. of moles of formed product are equal and is \frac{1}{8}th of mole of any of reactant.

Thus weight of  P_{4} O_{6} =\frac{3.80}{8}×220 ≈103.41

        weight of  P_{4} O_{10} =\frac{3.80}{8}×284 ≈133.48

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15 ounces so you can make it even
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