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Stells [14]
3 years ago
14

Write the equation of a line that is perpendicular to y=-2/7x + 9 and that passes through the point (-4,6) [FP]​

Mathematics
1 answer:
siniylev [52]3 years ago
7 0

Answer:

$y=(7/2)x+20$

Step-by-step explanation:

SInce the gradient of the first line is $-2/7$ then the gradien of the perpendicular line is $7/2$.

Therefore by the point slope formula the line that we are looking for is

$y-6=(7/2)(x+4)$

$y=(7/2)x + 20$

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kati45 [8]

Answer: y ≥ (3/5)*x - 3

Step-by-step explanation:

In the graph, we can see that we are above a bold line, that goes through the points (0, -3) and (5, 0)

First, let's find the equation for this line:

y = a*x + b

the value of a is the slope and is equal to:

a = (0 - (-3))/(5 -0) = 3/5

and the value of b is the point where the line intersects the y-axis, in this case, b = -3

then our line is

y = (3/5)*x - 3

As the shaded part is above the line, this equality represents the minimum value that y can take for a given x, and because the line is not a doted line, we know that the equality is valid, so we must use the ≥ symbol.

y ≥ (3/5)*x - 3

4 0
3 years ago
What is the solution of the equation 4.5+m=10
drek231 [11]

Answer:

The first thing that we need to do is subtract 4.5 from both sides because that would removed the 4.5 from the left side and leave us with m by itself.  So we get the following m=5.5 and that is our solution.

<u><em>Hope this helps!  Let me know if you have any questions</em></u>

6 0
2 years ago
Read 2 more answers
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dem82 [27]

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bank card is charging 1.4 monthly interest on credit card changes. If you charge $175 pair of running shoes on the card and did
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Step-by-step explanation:

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