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asambeis [7]
2 years ago
12

System software can be described as end-user software and is used to accomplish a variety of tasks.

Computers and Technology
1 answer:
irina [24]2 years ago
8 0
Your answer is false :)

I hope this helps! :)
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Importancia del sistema operativo
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3 years ago
Read 2 more answers
(Display four patterns using loops) Ask the user to enter an integer to
fomenos

Answer:

Hi There was small mistake. It is working fine for me. When you run from command line - use LoopPattern, not looppatern

import java.util.Scanner;

public class Looppattern {

  public static void main(String[] args) {

      Scanner sc = new Scanner(System.in);

      System.out.println("Enter how man levels you need: ");

      int levels = sc.nextInt();

      System.out.println("\n---------------Pattern A-----------------\n");

      for (int p = 1; p <= levels; p++) {

          for (int k = 1; k <= p; k++) { // increasing each level printing

              System.out.print(k);

          }

          System.out.println();

      }

      System.out.println("\n---------------Pattern B-----------------\n");

      int r = levels;

      for (int p = 1; p <= levels; p++) {

          for (int k = 1; k <= r; k++) {

              System.out.print(k);

          }

          r--; // decreasing levels

          System.out.println();

      }

      System.out.println("\n---------------Pattern C-----------------\n");

      for (int p = 1; p <= levels; p++) { // here incresing

          for (int k = p; k > 0; k--) { // and here decreasing pattern to

                                          // achieve our required pattern

              System.out.print(k);

          }

          System.out.println();

      }

      System.out.println("\n---------------Pattern D-----------------\n");

      r = levels;

      for (int p = 1; p <= levels; p++) {

          for (int k = 1; k <= r; k++) {

              System.out.print(k);

          }

          r--; // decreasing levels

          System.out.println();

      }

  }

}

Explanation:

4 0
3 years ago
Reference variables allow arguments to be passed by ____________.
son4ous [18]

Answer:

Reference

Explanation:

The Reference type variable is such type of variable in C# that holds the reference of memory address instead of value. Examples for reference type are classes, interfaces, delegates and arrays.

We can pass parameters to the method by reference using <em>ref </em>keyword

It’s mandatory to initialize the variable value before we pass it as an argument to the method in c#

For example,

int x = 10;  // Variable need to be initialized

Add(ref x); // method call

If you pass parameters by reference in method definition, any changes made to it affect the other variable in method call.

Here's a sample program:

using System;

namespace ConsoleApplication

{

   public class Test

   {

       public static void Main()

       {

           int i = 10;

           Console.WriteLine("i=" + i);

           Add(ref i);

           Console.WriteLine("i=" + i);

           Console.ReadLine();

       }

       public static void Add( ref int j)

       {

           j = j + 10;

           Console.WriteLine("j="+j);

       }

   }

}

Output:

i=10

j=20

i=20

7 0
2 years ago
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