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2 years ago

How to write this in number form 4 less than the product of 6 and a number

Mathematics

1 answer:

saul85 [17]2 years ago

3 0

Answer:

6x - 4

Step-by-step explanation:

The problem is asking for 4 less than a number times 6. Set this number equal to x, leaving us with 4 less than 6x, or 6x - 4.

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Ted has $3.90. He has only dimes and quarters. He has 27 coins altogether. How many of each does he have

mestny [16]

Answer: 8 quarters 19 dimes

Step-by-step explanation:

we already know 8+19=27, if 4 quarters equals a dollar then you use 4 quarters each to create 2 dollars.

then, use 10 dimes to create another dollar summing it up to $3. now all we have to do is make 90 cents, and we've already used 18 coins.

if we used another 9 dimes, that would equal 90 cents.

in conclusion, 4+4= 8

8+10= 18

18+9= 27, and having $3.90

6 0

2 years ago

a survey of factories in five northeastern states found that 10% of the 300 workers surveyed were satisfied with the benefits of

DiKsa [7]

Well I don't know if i'm answering the question, but 30 workers surveyed were satisfied with the benefits they received from the employers because 300 multiplied by .10 is 30. Hope my answer is useful.

5 0

3 years ago

Renee uses 12 marshmallows and 8 graham crackers to make 4 s'mores. Drag marshmallows and graham crackers into the box to show h

Anit [1.1K]

To find out how much is needed for 1 you will need to divide each given value by 4:
12 marshmallows / 4 = 3
8 graham crackers / 4 = 2
4 smores / 4 = 1
you then need to multiply each value by 3 :
3 marshmallows x 3 = 9
2 graham crackers x 3 = 6
1 smore x 3 = 3
therefore the answer would be :
9 marshmallows
6 graham crackers

hope this helps you

7 0

3 years ago

Read 2 more answers

Find the range, median, first and third quartiles, and interquartile range for each data set OF THE NUMBERS 52 72 96 21 58 40 75

Andrej [43]

Answer:

Range: 75 Median: 58 1Q: 40 3Q: 75 Interquartile: 35

4 0

3 years ago

Find sin(a+B)

diamong [38]

Answer:

Cos A=5/13

we have

Cos² A= $1-Sin ²A$

25/169=1-Sin²A

sin²A=1-25/169

sin²A=144/169

Sin A= $\sqrt{144/169}=12/13$

again

Tan B=4/3

P/b=4/3

p=4

b=3

h= $\sqrt{3²+4²}=5$

Now

Sin B=p/h=4/5

in IV quadrant sin angle is negative so

Sin B=-4/5

CosB=b/h=3/5

Now

Sin(A+B):sinAcosB+CosAsinB

now 

substitute value

Sin(A+B):12/13*3/5+5/13*(-4/5)=36/65-4/13

=16/65 is a required answer

6 0

2 years ago