Answer:
Step-by-step explanation:
\[2~ sin^2 x+3sin x+1=0\]
\[2sin^2x+2sin x+sin x+1=0\]
2sinx(sin x+1)+1(sin x+1)=0
(sin x+1)(2 sin x+1)=0
either sin x+1=0
sin x=-1=sin 3π/2=sin (2nπ+3π/2)
x=2nπ+3π/2,where n is an integer.
or 2sin x+1=0
sin x=-1/2=-sin π/6=sin (π+π/6),sin (2π-π/6)=sin (2nπ+7π/6),sin (2nπ+11π/6)
x=2nπ+7π/6,2nπ+11π/6,
where n is an integer.
Answer:
left 2 and 8
right 2 and 4
Step-by-step explanation:
For each equation at the top you substitute the number into x for the numbers on the left
y=2(1)^2
y=2
y=2(2)^2
y=8
y=2^1
y=2
y=2^2
y=4
Answer:
x=2
Step-by-step explanation:
let the number be x
9x-8=6+2x
9x-2x=6+8
7x=14
x=14/7
x=2
Answer:
can I see a copy of the picture? I will edit answer once I can see the picture of the gingerbread man
