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3 years ago

What is the decimal .387123 rounded to the nearest thousand

2 answers:

6 0

It is the nearest thousandth which is the third decimal place. The answer would be .387 unless the 1 was a 5 or higher then it would be .388

kirill [66]3 years ago

5 0

0.387123

Note the place value of each digit

0
.
3 (tenths)
8 (hundredths)
7 (thousandths)
1 (ten thousandths)
2 (hundred thousandths)
3 (millionths)

to find the nearest thousandths, look at the place value of the ten thousandths. It is a 1. Because it is less than 5, you round down.

0.387123 becomes 0.387

0.387 is your answer

hope this helps

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Deena took six final exams and received these scores:<br> 65, 72, 79, 86, 93, 100.

mash [69]

Answer:for the first exam she made a 65 for the second one she made a 72 for the third one she made a b for the forth one she made a 86 for the fifth one its b and replace it with a c for the last one she made a d

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2 years ago

How do you write 14/12 and 31/10 as a mixed number

Naddik [55]

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31/10= 3 and 1/10

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4 years ago

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The following formula can be used to find the distance that a person has run. distance = rate · time How far has a person travel

Nataly_w [17]

It is a trick question. multiply 5.5 times 0.75=4.125

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4 years ago

Please be quick! i need answer for each in the box, giving 15 points

Anastaziya [24]

The solutions are $f(-2)=12, f(-1)=7, f(0)=2, f(1)=-3$ and $f(2)=-8$

Explanation:

To find the values of f(x), we need to substitute the values for x in the function $f(x)=2-5x$

For $x=-2$ ,

$\begin{aligned}f(x) &=2-5 x \\&=2-5(-2) \\&=2+10 \\&=12\end{aligned}$

Thus, $f(-2)=12$

For $x=-1$ ,

$\begin{aligned}f(-1) &=2-5(-1) \\&=2+5 \\&=7\end{aligned}$

Thus, $f(-1)=7$

For $x=0$ ,

$\begin{aligned}f(0) &=2-5(0) \\&=2+0 \\&=2\end{aligned}$

Thus, $f(0)=2$

For $x=1$ ,

$\begin{aligned}f(1) &=2-5(1) \\&=2-5 \\&=-3\end{aligned}$

Thus, $f(1)=-3$

For $x=2$ ,

$\begin{aligned}f(2) &=2-5(2) \\&=2-10 \\&=-8\end{aligned}$

Thus, $f(2)=-8$

Hence, the solutions are $f(-2)=12, f(-1)=7, f(0)=2, f(1)=-3$ and $f(2)=-8$

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3 years ago

Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions:

grigory [225]

Answer:

Part A: The graph of the system is plotted at y-intercepts of 3 and -4. The line of the first equation is dashed and shaded below. The line of the second equation is dashed and shaded above. The solution area is between the second and third quadrants.

Part B: No, the point (-4, 6) is not in the solution are because it only fits into the first equations solution area. [6=2(-4)+3 solved is 6=-5, this is not a true statement.]

Step-by-step explanation:

Part A: Each equation {y>2x+3, y<-3/2x-4} is already in slope intercept form and can be graphed. In the first equation we know that there is a y-intercept of 3 and a slope of 2. This is shown as as a upward moving line with plot points such as (-2,-1), (-1,1), (0,4), (1,6), and so on. In the second equation we know that there is a y-intercept of -4 and a slope of -3/2. This is shown as a downward moving line with plot points such as (0,-4), (-2,-1), (-4, 2), and so on. (See graph below)

Part B: The plot point (-4, 6) is not included in the solution area of the systems. This can be seen on the graph. And, proven mathematically by plugging in the point into the equations:

y=2x+3 plug in the points (6)=2(-4)+3
solve (6)=2(-4)+3 ... 2(-4)=-8 ... -8+3=-5 ... 6 = -5 is not a true statement

So, already we know that this plot point is not an answer to the system. Let's continue anyway.

y=-3/2x-4 plug in the points (6)=-3/2(-4)-4
solve (6)=-3/2(-4)-4 ... -3/2(-4)= 6 ... 6-4 = 2 ... 6=2 is not a true statement.

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3 years ago