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Mariana [72]
3 years ago
12

Batteries can supply a steady flow of electrons. True False

Physics
1 answer:
Alecsey [184]3 years ago
6 0

The answer is TRUE, batteries CAN supply a steady flow of electrons.

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A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t
marishachu [46]

Answer:

The impact occured at a distance of 2478.585 meters from the person.

Explanation:

(After some research on web, we conclude that problem is not incomplete) The element "Part A" may lead to the false idea that question is incomplete. Correct form is presented below:

<em>A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 6.4 seconds apart. How far away did the impact occur? (Sound speed in the air: 343 meters per second, sound speed in concrete: 3000 meters per second)</em>

Sound is a manifestation of mechanical waves, which needs a medium to propagate themselves. Depending on the material, sound will take more or less time to travel a given distance. From statement, we know this time difference between air and concrete (\Delta t), in seconds:

\Delta t = t_{A}-t_{C} (1)

Where:

t_{C} - Time spent by the sound in concrete, in seconds.

t_{A} - Time spent by the sound in the air, in seconds.

By suposing that sound travels the same distance and at constant speed in both materials, we have the following expression:

\Delta t = \frac{x}{v_{A}}-\frac{x}{v_{C}}

\Delta t = x\cdot \left(\frac{1}{v_{A}}-\frac{1}{v_{C}}  \right)

x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}}  } (2)

Where:

v_{C} - Speed of the sound in concrete, in meters per second.

v_{A} - Speed of the sound in the air, in meters per second.

x - Distance traveled by the sound, in meters.

If we know that \Delta t = 6.4\,s, v_{C} = 3000\,\frac{m}{s} and v_{A} = 343\,\frac{m}{s}, then the distance travelled by the sound is:

x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}}  }

x = 2478.585\,m

The impact occured at a distance of 2478.585 meters from the person.

7 0
3 years ago
Can someone check my answers pls
o-na [289]
Hmmm... I’d say that’s pretty accurate. Good job! Well wishes on whatever it is you’re doing.
7 0
4 years ago
A 1 kilogram ball has 8 joules of kinetic energy. what is its speed
ivann1987 [24]
KE =  \frac{1}{2}mv^{2} \\ v =  \sqrt{ \frac{2KE}{m} }  \\ v =  \sqrt{ \frac{2*8J}{1kg} } \\ v = 4m/s

Therefore, the ball has a velocity of 4m/s.
6 0
3 years ago
Compared to your mass on earth, on the moon your mass would be
nirvana33 [79]
I believe your mass on the moon would be lighter than on earth because there is no gravity on the moon
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3 years ago
_____ bodies help in reducing friction
amm1812
Do you have options?
6 0
3 years ago
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