Batteries can supply a steady flow of electrons.<br> True<br> False

What feature of the ocean basin is formed when old oceanic crust is forced under continental plates?

Sholpan [36]

Answer:

Mid ocean ridge is formed when old oceanic crust is forced under continental plates.

Explanation:

Ocean basin is a kind of land surface that is present under an ocean and below the water.

Ocean basin contain continental shelf,mid ocean ridge that is found on the sea floor.

The size of ocean basin is equal to the size of an ocean and is found below the ocean.

When, water covers the earth's crust region in the distant past,ocean basin formation occurs.This prcess require long time as spreading of sea floor and tectonic plates takes place.

Ex-Atlantic Ocean basin is formed over million years that is present in the European Continent.

4 0

3 years ago

Which waves are used in medicine?

Reika [66]

Answer:

C

Explanation:

4 0

3 years ago

What precautions should you take when working with electronic equipment?

ollegr [7]

Answer:

Be sure to unplug the power source of all electrical equipment before working on it. Always pull from the plug, not the cord. Always wear proper non conductive clothing – insulated gloves, non conductive protective apparel and shoes with insulated soles. Avoid loose clothing or ties.

7 0

3 years ago

A 300 MHz electromagnetic wave in air (medium 1) is normally incident on the planar boundary of a lossless dielectric medium wit

Masja [62]

Answer:

Wavelength of the incident wave in air = 1 m

Wavelength of the incident wave in medium 2 = 0.33 m

Intrinsic impedance of media 1 = 377 ohms

Intrinsic impedance of media 2 = 125.68 ohms

Check the explanation section for a better understanding

Explanation:

a) Wavelength of the incident wave in air

The frequency of the electromagnetic wave in air, f = 300 MHz = 3 * 10⁸ Hz

Speed of light in air, c = 3 * 10⁸ Hz

Wavelength of the incident wave in air:

$\lambda_{air} = \frac{c}{f} \\\lambda_{air} = \frac{3 * 10^{8} }{3 * 10^{8}} \\\lambda_{air} = 1 m$

Wavelength of the incident wave in medium 2

The refractive index of air in the lossless dielectric medium:

$n = \sqrt{\epsilon_{r} } \\n = \sqrt{9 }\\n =3$

$\lambda_{2} = \frac{c}{nf}\\\lambda_{2} = \frac{3 * 10^{6} }{3 * 3 * 10^{6}}\\\lambda_{2} = 1/3\\\lambda_{2} = 0.33 m$

b) Intrinsic impedances of media 1 and media 2

The intrinsic impedance of media 1 is given as:

$n_1 = \sqrt{\frac{\mu_0}{\epsilon_{0} } }$

Permeability of free space, $\mu_{0} = 4 \pi * 10^{-7} H/m$

Permittivity for air, $\epsilon_{0} = 8.84 * 10^{-12} F/m$

$n_1 = \sqrt{\frac{4\pi * 10^{-7} }{8.84 * 10^{-12} } }$

$n_1 = 377 \Omega$

The intrinsic impedance of media 2 is given as:

$n_2 = \sqrt{\frac{\mu_r \mu_0}{\epsilon_r \epsilon_{0} } }$

Permeability of free space, $\mu_{0} = 4 \pi * 10^{-7} H/m$

Permittivity for air, $\epsilon_{0} = 8.84 * 10^{-12} F/m$

ϵr = 9

$n_2 = \sqrt{\frac{4\pi * 10^{-7} *1 }{8.84 * 10^{-12} *9 } }$

$n_2 = 125.68 \Omega$

c) The reflection coefficient,r and the transmission coefficient,t at the boundary.

Reflection coefficient, $r = \frac{n - n_{0} }{n + n_{0} }$

You didn't put the refractive index at the boundary in the question, you can substitute it into the formula above to find it.

$r = \frac{3 - n_{0} }{3 + n_{0} }$

Transmission coefficient at the boundary, t = r -1

d) The amplitude of the incident electric field is $E_{0} = 10 V/m$

Maximum amplitudes in the total field is given by:

$E = tE_{0}$ and $E = r E_{0}$

E = 10r, E = 10t

3 0

3 years ago

Why do you think medical illustrations are important to the study of human biology?

Fofino [41]

Answer:

Personally, I am sure that learning everything by looking at image is more effective than looking at a forest of letters. As for the field of science as human biology, it is very very important as well, because the illustrations are vital resource to convey important medical information that is easier to understand by showing it as a drawing rather than by only describing it with text.

Explanation:

5 0

3 years ago

Batteries can supply a steady flow of electrons. True False