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77julia77 [94]
2 years ago
12

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

g 30 centimeters. How much work is done in stretching the spring from 50 centimeters to 80 centimeters
Physics
1 answer:
natima [27]2 years ago
5 0

The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.

<h3>Hooke's Law</h3>

Hooke's law states that the force applied to an elastic material is directly proportional to its extension, provided its elastic limit is not exceeded.

To calculate the amount of work done by Hooke's law, first, we need to find the force constant of the spring.

Formula:

  • F = ke................. Equation 1

Where:

  • F = Force applied
  • k = Spring constant
  • e = extension

make k the subject of the equation

  • k = F/e................ Equation 2

From the question,

Given:

  • F = 450 N
  • e = 30 cm = 0.3 m

Substitute these values into equation 2

  • k = 450/0.3
  • k = 1500 N/m.

Finally, To find the work done in stretching the spring from 50 cm to 80 cm, we use the formula below.

  • W = ke²/2........... Equation 3

Where:

  • W = Work done
  • k = spring constant
  • e = extension

Also, From the question,

Given:

  • e = (80-50) = 30 cm = 0.3 m
  • k = 1500 N/m

Substitute these values into equation 3

  • W = 1500(0.3²)/2
  • W = 67.5 J.

Hence, The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.

Learn more about Hooke's law here: brainly.com/question/12253978

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Answer:

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Explanation:

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If we have 10 wires of resistance R/10 each and connect them in parallel, the equivalent resistance is:

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This sum is repeated 10 times. Operating each term:

\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}

All the terms have the same denominator, thus:

\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}

Taking the reciprocals:

R_e=R/100

The equivalent resistance of the combination is R/100

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T-mg = m\frac{v^2}{R}

where

T is the tension in the string, which points upward

mg is the weight of the string, which points downward, with

m = 0.158 kg being the mass of the ball

g = 9.8 m/s^2 being the acceleration due to gravity

m \frac{v^2}{R} is the centripetal force, which points upward, with

v = 5.22 m/s being the speed of the ball

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Substituting numbers and re-arranging the formula, we find T:

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2) 3.9 N

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