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postnew [5]
2 years ago
14

How much potintial energy is in a closed system where the height of the object is 2 m, and the mass is 10 kg?

Physics
2 answers:
Dovator [93]2 years ago
8 0

Answer:

<u>Answer</u><u>:</u><u> </u><u>B</u><u>.</u><u> </u><u>1</u><u>9</u><u>6</u><u> </u><u>J</u>

• potential energy is calculated from the formula:

{ \tt{p.e = mgh}}

• m = 10 kg

• g = 9.81 m/s²

• h = 2m

→ Substitute:

{ \tt{p.e = (10) \times (2) \times (9.81)}} \\  \\ → \: { \boxed{ \tt{potential \: energy = 196.2 \:  \: joules}}}

Lorico [155]2 years ago
6 0

Answer:

D. 196 J

Explanation:

PE=mgh=10×9.8×2=196J

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3 years ago
Susan's 10.0kg baby brother Paul sits on a mat. Susan pulls the mat across the floor using a rope that is angled 30? above the f
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Answer:

The speed after being pulled is 2.4123m/s

Explanation:

The work realize by the tension and the friction is equal to the change in the kinetic energy, so:

W_T+W_F=K_f-K_i (1)

Where:

W_T=T*x*cos(0)=32N*3.2m*cos(30)=88.6810J\\W_F=F_r*x*cos(180)=-0.190*mg*x =-0.190*10kg*9.8m/s^{2}*3.2m=59.584J\\ K_i=0\\K_f=\frac{1}{2}*m*v_f^{2}=5v_f^{2}

Because the work made by any force is equal to the multiplication of the force, the displacement and the cosine of the angle between them.

Additionally, the kinetic energy is equal to \frac{1}{2}mv^{2}, so if the initial velocity v_i is equal to zero, the initial kinetic energy K_i is equal to zero.

Then, replacing the values on the equation and solving for v_f, we get:

W_T+W_F=K_f-K_i\\88.6810-59.5840=5v_f^{2}\\29.097=5v_f^{2}

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So, the speed after being pulled 3.2m is 2.4123 m/s

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3 years ago
Two bowling balls each have a mass of 6.8 kg. They are located next to each other with their centers 21.8 cm apart. What gravita
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