10.7 rad/s is the final angular velocity of the stick.
Given:
Mass of the stick = 4.42 kg
Length of the stick = 1.23m
Force of impulse (I) = 12.8 N s
The linear velocity of the stick,
Therefore, the final linear velocity of the stick is 2.89 m/s
∴
Therefore, 10.7 rad/s is the final angular velocity of the stick.
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Answer:
The atomic number increases by 1.
Explanation:
The beta minus decay is a process in which a neutron decays into a proton, emitting an electron and an anti-neutrino:
If this process occurs inside an unstable nucleus, we notice that:
- a neutron is converted into a proton, therefore
- the number of neutrons decreases by 1 and the number of protons increases by 1
Keep in mind that the atomic number of a nucleus corresponds to the number of protons it contains: therefore, since this number increases by 1, then the atomic number increases by 1.
Answer:
9000RPM
Explanation:
"Angular velocity" is directly related to kinetic energy, that is, the Kinetic energy equation would allow an approximation to the resolution investigated in the problem.
The equation for KE is given by:
Now, starting from there towards the <em>Angular equation of kinetic energy</em>, the moment of inertia (i) is used instead of mass (m), and angular velocity (w) instead of linear velocity (V)
That's how we get
calculating the inertia for a solid cylindrical disk, of
m = 400kg
r = 1.2 / 2 = 0.6m
We understand that the total kinetic energy is 3.2 * 10 ^ 7J, like this:
Thus,
943 rad / s ≈ 9000 rpm