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Olegator [25]
3 years ago
9

Find expressions for the force needed to bring an object of mass m from rest to speed v in time t. express your answer in terms

of the variables m, v, and t.
Physics
1 answer:
VARVARA [1.3K]3 years ago
3 0
Good morning.

We have that:

\mathsf{V = a\cdot t} , since we have rest in the inicial time.

The acceleration can be found with Newton's Law:

\mathsf{F = m\cdot a\iff a = \dfrac{F}{m}}

Now we put the acceleratin in the velocity equation:

\mathsf{V = \dfrac{F}{m} \cdot t}

We want the force, so, let's isolate F:

\mathsf{V\cdot m = F\cdot t}\\ \\ \\ \boxed{\mathsf{F = \dfrac{V\cdot m}{t}}}

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Uphill escape ramps are sometimes provided to the side of steep downhill highways for trucks with overheated brakes. For a simpl
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Answer:

404.4 m

Explanation:

Converting the initial speed from km/h to m/s then

140\times \frac {1000m}{3600s}=38.88888889 m/s \approx 38.89 m/s

The acceleration is resolved as shown in the figure hence

deceleration of the truck along the inclined plane will be

a=-g sin \theta where g is acceleration due to gravity

Substituting g with 9.81 m/s^{2} then

a=-9.81 m/s^{2} sin 11^{\circ}=-1.871836245\approx -1.87 m/s^{2}

Using kinematic equation

v^{2}=u^{2}+2as and making s the subject then

s=\frac {v^{2}-u^{2}}{2a} where v and u are final and initial velocities respectively

Substituting 0 for v, 38.89 m/s for u and -1.87 m/s^{2} then

s=\frac {0^{2}-38.89^{2}}{2\times -1.87}=404.3936096 m\approx 404.4 m

3 0
3 years ago
In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres w
NeTakaya

Answer:

F=2.47*10^{-10} N

Explanation:

The gravitational force is calculated by using

F=G\frac{M_1M_2}{r^2}

G: Cavendish constant = 6.67*10^{-12}Nm^2/kg^2

r=2.30cm=0.023m

M1=1.4kg

M2=14.0g=0.014kg

By replacing we have

F=2.47*10^{-10} N

hope this helps!!

6 0
3 years ago
Read 2 more answers
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