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Olegator [25]
3 years ago
9

Find expressions for the force needed to bring an object of mass m from rest to speed v in time t. express your answer in terms

of the variables m, v, and t.
Physics
1 answer:
VARVARA [1.3K]3 years ago
3 0
Good morning.

We have that:

\mathsf{V = a\cdot t} , since we have rest in the inicial time.

The acceleration can be found with Newton's Law:

\mathsf{F = m\cdot a\iff a = \dfrac{F}{m}}

Now we put the acceleratin in the velocity equation:

\mathsf{V = \dfrac{F}{m} \cdot t}

We want the force, so, let's isolate F:

\mathsf{V\cdot m = F\cdot t}\\ \\ \\ \boxed{\mathsf{F = \dfrac{V\cdot m}{t}}}

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A car is traveling clockwise around a circular racetrack of radius 1440m. When the car is at the northernmost point of the circl
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A 1.0-kg standard cart collides on a low-friction track with cart A. The standard cart has an initial x component of velocity of
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Answer:

Explanation:

Mathematically, linear momentum is expressed as the product of mass and velocity. Linear momentum conservation law states that a body or system of bodies retains its total momentum unless an external force is applied to the system.

In this case, the system consists of two carts.

At the start, the linear momentum (P) of the system is equal to:

P=1.0kg*0.4m/s=0.4kg*m/s

It's only composed of linear momentum of the standard cart because cart A doesn't have any linear momentum at that moment.

After the collision, linear momentum has to be the same

P=0.4kg*m/s=1.0kg*0.20m/s+m_{A} *0.70m/s

where m_A is the mass of the cart A.

Solving for m_A

m_{A} =0.28kg

After the cart A rebounds, the linea momentum of the system has changed (because of the force present in the rebound). The new linear momentum is:

P=1kg*0.2m/s+0.29kg*(-0.7m/s)=-0.003kg*m/s

Then, the lump of putty is added to the system, but the linear momentum has to be the same, because we added a mass, not a force. The mass of that putty (m_p) has to be added to the equation of the system

-0.003kg*m/s=1.0kg*(-0.2m/s)+(0.29kg+m_{p} )(0.4m/s)

Solving for m_p

m_{p}=0.20kg

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For each of the following decays or reactions, name at least. one conservation law that prevents it from occurring.(c) p → π⁺ +
Amanda [17]

(c)p→π⁺₊π⁺₊π

Baryon number is +1 on the left side of the equation, 0 on the

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<h3>How do you determine whether a baryon number is conserved?</h3>

  • According to the law of conservation of baryon number, the sum of the baryon numbers of all incoming particles equals the sum of the baryon numbers of all particles produced by the reaction. Energy, and so on, are conserved even if the incoming proton has sufficient energy and charge.
<h3>What is Baryon Number</h3>
  • In particle physics, the baryon number denotes which particles are baryons and which particles are not. Each baryon has a baryon number of 1, and each antibaryon has a baryon number of -1. Other non-baryonic particles have a baryon number of 0. Since there are exotic hadrons like pentaquarks and tetraquarks, there is a general definition of baryon number as:
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  • wheren_{q} represents the number of quarks and nq represents the number of antiquarks.

To learn more about Baryon Number refer to

brainly.com/question/10358797

#SPJ4

4 0
2 years ago
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