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3 years ago

Adrian's backyard pool contains 6.4 gallons of water. Adrian will begin filling his pool at a rate of 4.1 gallons per second,

Mathematics

1 answer:

Marina CMI [18]3 years ago

5 0

Answer:

the answer is 12

Step-by-step explanation:

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Read 2 more answers

From the top of a vertical cliff 50 m high, the angle of depression of an object that is level with the base of the cliff is 70°

Svetlanka [38]

Answer:

The distance of the object from the base of cliff is 18.24 meters

Step-by-step explanation:

Given as :

The height of the vertical cliff = h = 50 meters

The distance of the object from the base of cliff = x meters

Let The angle of depression of object that level with cliff base = Ф = 70°

<u>Now, from figure</u>

Tan angle = $\dfrac{\textrm perpendicular}{\textrm base}$

I.e TanФ = $\dfrac{\textrm AB}{\textrm OA}$

Or, TanФ = $\dfrac{\textrm h}{\textrm x}$

Or, Tan 70° = $\dfrac{\textrm 50 meters}{\textrm x meters}$

Or, 2.74 = $\dfrac{\textrm 50}{\textrm x}$

∴ x = $\dfrac{\textrm 50}{\textrm 2.74}$

I,e x = 18.24 meters

So, The distance of the object from the base of cliff = x = 18.24 meters

Hence,The distance of the object from the base of cliff is 18.24 meters Answer

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3 years ago