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aleksandr82 [10.1K]
4 years ago
8

What does the solvent do in a solution?

Chemistry
2 answers:
tiny-mole [99]4 years ago
6 0

Answer: The solvent is the substance that dissolves another in a solution

Explanation:

IrinaK [193]4 years ago
3 0
A solvent is dissolved in a solution. For example, salt water is a solution of a solute (water) and a solvent (salt.)
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What is the systematic name for the following structure, specifying cis-/trans-?
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cis-3,4-dimethyl-3-hexene

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Elemental iodine (I 2) is a solid at room temperature. What is the major attractive force that exists among different I 2 molecu
Ulleksa [173]

Explanation:

As I_{2} is a covalent compound because it is made up by the combination of two non-metal atoms. Atomic number of an iodine atom is 53 and it contains 7 valence electrons as it belongs to group 17 of the periodic table.

Therefore, sharing of electrons will take place when two iodine atoms chemically combine with each other leading to the formation of a covalent bonding.

Hence, weak forces like london dispersion forces will be present between a molecule of I_{2}.

The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

thus, we can conclude that london dispersion force is the major attractive force that exists among different I_{2} molecules in the solid.

7 0
4 years ago
Consider the Van der Vaals equation of state: (????+????????????)(????−????)=???????????? where p is pressure, V is volume, n is
yanalaym [24]

Answer:

Units of a = \frac{atm\ L^2}{mol^2}

Units of b = \frac{L}{mol}

Explanation:

The Van der Waal's equation  is:-

\left(P+\frac{an^2}{V^2}\right)\left(V-nb\right)=nRT

Where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value

a and b are van der Waal's constant

If pressure is taken in atm and volume in L. So,

P+\frac{an^2}{V^2} represents the pressure correction term. Then,

Units of a = \frac{atm\ L^2}{mol^2}

V-nb represents the volume correction term. Then,

Units of b = \frac{L}{mol}

6 0
3 years ago
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