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mafiozo [28]
3 years ago
5

The vacoule is most like a ?

Chemistry
2 answers:
Hoochie [10]3 years ago
5 0
Just listen to glad kk bye now ! :)
Feliz [49]3 years ago
3 0
Animal’s and plant cells
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If three electrons are available to fill three empty 2p atomic orbitals, how will the electrons be distributed in the three orbi
Sedaia [141]
Think of it this way: say orbitals are boxes and each box can contain 2 electrons.

If there are 3 boxes forming one orbital, it takes 6 electrons to completely fill it. Since there's less than six, each box takes one electron, so there's 1 electron per orbital.
5 0
3 years ago
Read 2 more answers
How many neutrons does an atom of<br> Copper have in its nucleus?
klasskru [66]
Answer:34.55
explanation:number of neutrons=mass number-atomic number
the mass number for copper is 63.55 so you do 63.55-29 (29 is the atomic number) and you would get 34.55
4 0
3 years ago
How many grams of iron metal do you expect to be produced when 325 grams of an 87.5 percent by mass iron (II) nitrate solution r
Debora [2.8K]
Answer: 88.2 g

Solution:

1) Chemical equation:

<span>2Al (s) + 3Fe(NO3)2 (aq) → 3Fe (s) + 2Al(NO3)3 (aq)

2) Theoretical molar ratios

2 mol Al : 3 mol Fe(NO3)2 : 3 mol Fe : 2 mol Al(NO3)3

3) Starting mass of pure iron nitrate

% = (mass of iron nitrate / mass of solution) * 100 = 87.5

=> mass of iron nitrate = 87.5 * mass of solution / 100

mass of solution = 325 g

=> mass of iron nitrate = 87.5 * 325 g / 100 = 284.375 g

4) moles of iron nitrate

moles = mass in grams / molar mass

molar mass of Fe(NO3)2 = 179.85 g/mol

moles = 284.375 g/ 179.85 g/mol = 1.58 moles Fe(NO3)2

5) proportion:

             x                                 3 mol Fe
--------------------------- =     ----------------------
1.58 mol Fe(NO3)2          3 mol Fe(NO3)2

Clear x:

x = 1.58 mol Fe

6) Convert 1.58 mol Fe into grams

mass = number of moles * atomic mass

atomic mass of iron = 55.845 g / mol

mass = 1.58 moles * 55.845 g/mol = 88.24 g

Rounded to 3 significant figures: 88.2 grams of Fe.
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6 0
3 years ago
A 5.00 liter gas sample is collected at a temperature and pressure of 27.0 degree C and 1.20 atm. It is desired to transfer the
kipiarov [429]

Answer:

The temperature of the gas in the 3.00 liter container, must be 150K

Explanation:

Let's apply the Ideal Gas Law, to find out the moles

P . V = n . R . T

1,20 atm . 5L = n . 0,082 L.atm/mol.K . 300 K

(1,20 atm . 5L) /  (0,082 mol.K/L.atm . 300 K) = n

6/24,6 mol = n = 0,244 moles

We have the moles now, so let's find the temperature in our new conditions.

P . V = n . R . T

1 atm . 3L = 0,244 moles . 0,082 L.atm/mol.K . T° in K

(1 atm . 3L / 0,244 moles . 0,082 mol.K/L.atm) = T° in K

3/20,008 K = T° in K = 150K

3 0
3 years ago
The layers of earth are the crust, mantle, and core, with the core being divided into inner and outer layers. Which of the follo
Westkost [7]

Answer:

C- The core is made up of dense elements, such as iron and nickel.

6 0
3 years ago
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