Let BS be the event that the patient survives bypass surgery.
Let H be the event that the heart damage will heal.
Then P(BS) = 0.60, and also we have a conditional probability: GIVEN that the patient survives,
the probability that the heart damage will heal is 0.5, that is P(H|BS) = 0.5
We want to know P(BS and H).
Using the formula of the conditional probability:
P(H and BS) = P(H|BS)·P(BS) = (0.6)(0.5) = 0.3
let 1st and 2nd no be x and y respectively
1st case:x=4y
2nd case:x-y=12
substituting the value of x in 2nd case
4y-y=12
3y=12
y=12÷3
y=4
now putting the value of y in 1st case
x=4×4
=16
I believe it is in the ten millionth place.
Answer:
3^2
Step-by-step explanation:
When multiplying, add the powers.
When dividing, minus the powers
3^3 * 3^3 / 3^4 = 3^(3 + 3 - 4) = 3^2
