Ask question

Ask question

All categories

3 years ago

8

Form a normally distributed population, a simple random sample of size 30 is taken. the mean of the sample is 144 and the standa

rd deviation of the sample is 12. which interval is the 90% confidence interval for the population mean?

1 answer:

Kisachek [45]3 years ago

3 0

The answer I think is D.

You might be interested in

IS 0.7878 A TERMINATING Decimal

Vladimir [108]

Answer:

If it continues its not if it stops it is.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Triangle DAN has coordinates D(-10,4), A(-4,1), and N(-2,5) Using coordinate geometry, prove that triangle DAN is a right triang

inn [45]

Answer:

75

Step-by-step explanation:

eeeeeeeeeeeeeeeeeeeeeeeee

8 0

3 years ago

An urn contains 7 red marbles and 3 white marbles. three marbles are drawn from the urn one after the other. find the probabilit

vaieri [72.5K]

7+3 = 10 total marbles

1st pick = 7/10 for a red one

2nd pick = 6/9 reduces to 2/3 for a red one

3rd pick = 3/8 for a white one

7/10 x 2/3 =14/30 reduces to 7/15

7/15 x 3/8 = 21/120 reduces to 7/40

probability = 7/40

5 0

3 years ago

Help me please<br><br><br><img src="https://tex.z-dn.net/?f=if%20%5C%3A%20%20%5Csin%28x%29%20%20%3D%20%20%5Ccos%2850degree%29%20

koban [17]

Answer:

x = 40°

Step-by-step explanation:

using the cofunction identity

cos(90 - x) = sin x , so

90 - x = 50 , then

x = 40

that is sin40° = cos50°

7 0

2 years ago

Jeffrey is using a copy machine to make posters for a school play. The machine prints the posters at a constant rate. After 3 mi

jasenka [17]

Answer:

B: 11 minutes.

Step-by-step explanation:

So, we know that the machine prints at a constant rate.

After 3 minutes, the machine prints 108 posters.

So, let’s find the <em>unit rate. </em>We will divide the output over the input. So:

$108\text{ posters}/3\text{ minutes}=36\text{ posters/min}$

So, the unit rate of the machine is 36 posters per minute.

We can write an equation. If t represent the number of minutes and p represent the amount of posters, then:

$p=36t$

Gives the amount of posters p and t minutes.

We want to know how long it will take Jeffrey to make 396 posters.

So, we can substitute 396 for p and solve for t. Hence:

$396=36t$

Divide both sides by 36:

$t=11$

Therefore, it will take Jeffrey 11 minutes to make 396 posters.

7 0

3 years ago