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Dimas [21]
2 years ago
13

Hello can you please help me posted picture of question

Mathematics
1 answer:
LuckyWell [14K]2 years ago
5 0
The medals can be awarded 96,860 different ways
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Find the equation of a line with a slope of 1 and passing through (11;3)
romanna [79]

Step-by-step explanation:

slope(m)=(Y-Y1)/X-X1

here,

M=1

(X1,Y1)=(11,3)

NOW,

m=(Y-Y1)/(X-X1)

1=(Y-3)/(X-11)

1×(X-11)=Y-3

X-11=Y-3

X-Y-11+3=0

X-Y-8=0

X-Y=0 is the required equation.

3 0
2 years ago
Simplify the expression:<br> (2p + 1)(2) =
Oxana [17]

Answer:

4p +2

Step-by-step explanation:

(2p + 1)(2)

Distribute

2p * 2 + 1*2

4p +2

5 0
2 years ago
Read 2 more answers
Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0
3 years ago
denny can deliver 6 papers every 15 minutes and brendan can deliver 5 papers in that same amount of time. how many papers can th
Evgesh-ka [11]

So for this problem you know that 15 is 1/4 of an hour so to get the amount of papers each individual could deliver by themselves in an hour you would multiply the amount they can deliver in 15 minutes by 4. Denny delivers 6 so multiplying that by 4 is 24. Next Brendan delivers 5 in 15 minutes so multiplying that by 4 you get 20. The final step is to add 20 and 24 to get the total amount of papers between the two of them that gets delivered in an hour. This will result in your answer of 44.

7 0
3 years ago
Read 2 more answers
Need help just with number 2 please and thank you!!
BaLLatris [955]
I believe the answer is 17
4 0
3 years ago
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