An object is lifted from the surface of aspherical planet to an altitude equal to the radius of the planet.As a result, what hap
1 answer:
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Answer:
Explanation:
Capacity of a parallel plate capacitor C = ε₀ A/ d
ε₀ is permittivity whose value is 8.85 x 10⁻¹² , A is plate area and d is distance between plate.
C =( 8.85 X10⁻¹² X 27 X 10⁻⁴ ) / 3 X 10⁻³
= 79.65 X 10⁻¹³ F.
potential diff between plate = Charge / capacity
= 4.8 X 10⁻⁹ / 79.65 X 10⁻¹³
= 601 V
Electric field = V/d
= 601 / 3 x 10⁻³
= 2 x 10⁵ N/C
Force on proton
= charge x electric field
1.6 x 10⁻¹⁹ x 2 x 10⁵
= 3.2 x 10⁻¹⁴
Acceleration a = force / mass
= 3.2 x 10⁻¹⁴ / 1.67 x 10⁻²⁷
= 1.9 x 10¹³ m s⁻²
Distance travelled by proton = 3 x 10⁻³
3 x 10⁻³ = 1/2 a t²
t =
t = 1.77 x 10⁻⁸ s
Answer:
Minimize the elevation or jump distance
Explanation:
The only action that minimizes, the impact force is to reduce as much as possible the height of the jump, the dog, ie the height from the jump point of the building. Since at the time of the jump its speed will increase every second at the rate of 9 [m/ s], that is this low effect of the gravitational acceleration of 9 [m/s^2]
where:
vf = final velocity [m/s]
g = gravity [m/s^2]
h = elevation [m]
As we can see while there is higher height, at a higher speed will impact the ground.