Question

A ray of light is moving from a material having a high indexof refraction into a material with a lower index of refraction.

Answer 1

Answer:

Away from the normal

Explanation:

The direction toward which the ray of light bend can be found by using Snell's law:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where

n1, n2 are the index of refraction of the first and second medium

$\theta_1, \theta_2$ are the angle of the incident and refracted ray with respect to the normal to the surface

Here, the ray of light moves from a material with high index of refraction to a material with lower index, therfore we have

$n_1 > n_2$

Re-arranging Snell's equation we get

$sin \theta_2 = \frac{n_1}{n_2} sin \theta_1$

and since

$\frac{n_1}{n_2}>1$

we find

$sin \theta_2 > sin \theta_1\\\theta_2 > \theta_1$

which means that the ray of light bends away from the normal.