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makkiz [27]
3 years ago
6

According to Newton’s second law of motion, the acceleration of an object equals the net force acting on the object divided by t

he object’s
Physics
2 answers:
Montano1993 [528]3 years ago
7 0

Answer:mass

Explanation:

Umnica [9.8K]3 years ago
5 0
Weight and mass of the object
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A compound eye __________. ANSWER Unselected is composed of thousands of prisms that focus light onto only a few photoreceptor c
babymother [125]

Answer:

contains many individual light detectors, each with its own lens

Explanation:

The compound eye is found mainly in insects and crustaceans, it is composed of individual receptor units, each with its focus, sensing nerve; each one gives a small image of the environment, so the image is mosaic type, not a complete integral image of the environment.

When reviewing the different statements, the correct one is

contains many individual light detectors, each with its own lens

8 0
3 years ago
If a weightlifter used 1,200 newtons of force to lift a barbell to a height of 2.5 meters in 3 seconds, how much work did he do?
Blizzard [7]
C.)  Work done = Force x displacement = 1200 x 2.5 = 3000 J. Hope this helps!
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3 years ago
A wave is a disturbance that carries from one place to another through matter of space
krok68 [10]

There's supposed to be a blank in the statement, where the answer is supposed to be inserted.

The question is supposed to say: "A wave is a disturbance that carries ______ from one place to another through matter or space".

To answer the question, write the word "<em>energy</em>" in the blank.

4 0
3 years ago
For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is
ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)

where A(t)=A₀e^{\frac{-bt}{2m}}

 A₀ is the amplitude at t=0 and

w' is the angular frequency of damped SHM, which is given by,

w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

Now coming to the problem,

Given: m=1.2 kg

           k=9.8 N/m

           b=210 g/s= 0.21 kg/s

           A₀=13 cm

a) A(t)=A₀/8

⇒A₀e^{\frac{-bt}{2m}} =A₀/8

⇒e^{\frac{bt}{2m}}=8

applying logarithm on both sides

⇒\frac{bt}{2m}=ln(8)

⇒t=\frac{2m*ln(8)}{b}

substituting the values

t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)

b) w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}

T'=\frac{2\pi}{w'}, where T' is time period of damped SHM

⇒T'=\frac{2\pi}{2.86}=2.2s

let n be number of oscillations made

then, nT'=t

⇒n=\frac{24}{2.2}=11(approx)

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4 years ago
Where is the fish in reality
vazorg [7]
In reality, the fish are in the ocean.
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3 years ago
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