Answer:
t = 50 min
so no answer is correct, the closest is C
Explanation:
In this exercise we must start by finding the distance between the stations using the graph,
let's divide the work into 3 parts
part 1 with relate constant
v₁ = v₀ + a₁ t₁
from the graph we see that it starts with zero velocity v₀ = 0
a₁ = v₁ / t₁
To have all the magnitudes in the same units, let's reduce the time to hours
t₁ = 1 min (1 h / 60 min) = 0.0166 h
a₁ = 50 / 0.01666
a₁ = 3000 km / h²
now let's find the distance traveled
x₁ = v₀ t₁ + ½ a₁ t₁²
x₁ = 0 + ½ 3000 (1/60)²
x₁ = 0.41666 km
Part 2 with constant velocity
v₁ = x₂ / t₂
t₂ = 5-1 = 4 min
t₂ = 4/60 h
x₂ = v₁ t₂
x₂ = 50 (4/60)
x₂ = 3.33333 km
Part 3 braking to a stop
v = v₁ + a₃ t₃
final velocity is zero v = 0
t₃ = 8-5 = 3 min
t₃ = 3/60 = 1/20 h
t₃ = 0.05 s
a₃ = v₁ / t₃
a₃ = 50 / 0.05
a₃ = 1000 km / h₂
x₃ = v₁ t - ½ a₃ t₃³
x₃ = 50 0.05 - ½ 1000 0.05²
x₃ = 1.25 km
the total distance between the two stations is
x_total = x₁ + x₂ + x₃
x_total = 0.416666 + 3.33333 + 1.25
x_toal = 4.999999 km
Taking the distance between the stations, we can calculate the time it takes man to travel them
v_man = x_total / t
t = x_total / v_man
t = 4.999999 / 6
t = 0.833332 h
t = 49.99999 min
t = 50 min
the time it takes is 50 min, so no answer is correct, the closest is C