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3 years ago

How should Tika most likely describe this relationship between force and distance to her study group

Physics

2 answers:

omeli [17]3 years ago

7 0

Answer:

Force is work done divided by distance

Explanation:

Work done to an object is given as rhe product of force and diatance moved, hence expressed as W=Fd where F is the applied force in Newtons, d is diatance moved in meters and W is work. The relationship between force and distance then is found by making either F or d the subject hence

$F=\frac {W}{d}\\d=\frac {W}{F}$

hence we can say that distance is given by dividing work by force or alternatively Force is relates to distance by dividing work done by distance. Both are correct.

tigry1 [53]3 years ago

3 0

Answer:

Explanation:

If the input force is less than the output force, then the input distance must be greater than the output distance.

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Uranium-235 decays to thorium-231 with a half-life of 700 million years. When a rock was formed, it contained 6400 million urani

Dahasolnce [82]

Answer:

proof in explanation

Explanation:

First, we will calculate the number of half-lives:

$n = \frac{t}{t_{1/2}}$

where,

n = no. of half-lives = ?

t = total time passed = 2100 million years

$t_{1/2}$ = half-life = 700 million years

Therefore,

$n = \frac{2100\ million\ years}{700\ million\ years}\\\\n = 3$

Now, we will calculate the number of uranium nuclei left ( $n_u$ ):

$n_u = \frac{1}{2^{n} }(total\ nuclei)\\\\n_u = \frac{1}{2^{3} }(6400\ million)\\\\n_u = \frac{1}{8}(6400\ million)\\\\n_u = 800\ million$

and the rest of the uranium nuclei will become thorium nuclei ( $u_{th}$ )

$n_{th} = total\ nuclei - n_u\\n_{th} = 6400\ million-800\ million\\n_{th} = 5600\ million$

dividing both:

$\frac{n_{th}}{n_u}=\frac{5600\ million}{800\ million} \\\\n_{th} = 7n_u$

<u>Hence, it is proven that after 2100 million years there are seven times more thorium nuclei than uranium nuclei in the rock.</u>

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