Answer:
Step-by-step explanation:
length=4×28=112 mm=11.2 cm
three centers form an equilateral triangle each side=2×28=56mm=5.6 cm
to find the height
h=√(5.6²-2.8²)=2.8√3
width=2.8+2.8√3+2.8=5.6+2.8√3=2.8(2+√3)
area=11.2×2.8(2+√3)≈117.03 7cm²≈117 cm²
C . 250 cm^2
cause its the same
Answer:
A(1) = 3, A(2) = 5, A(3) = 8, A(4) = 12, A(5) = 17
Step-by-step explanation:
Given A(n) = n + A(n–1) a1 = 3.
A(1) = 3.
A(2) = (2) + A(2–1)
= (2) + A(1)
= (2) + (3) = <u>5</u>
A(3) = (3) + A(3-1)
= (3) + A(2)
= (3) + (5) = <u>8</u>
A(4) = (4) + A(4–1)
= (4) + A(3)
= (4) + (8) = <u>12</u>
A(5) = (5) + A(5–1)
= (5) + A(4)
= (5) + (12) = <u>17</u>
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
