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3 years ago

Kasih tau caranya dong

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

6 0

C . 250 cm^2

cause its the same

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Hat is the metric system prefix for the quantity 0.000 001?

mezya [45]

In the metric system, you give a name to the following multiples: 10, 100, 1000, 0.1, 0.01, 0.001, and then you skip three places. So, you have

$\left.\begin{array}{cc}\vdots&\vdots\\1000000&\text{mega}\\1000&\text{kilo}\\100&\text{hecto}\\10&\text{deca}\\0.1&\text{deci}\\0.01&\text{centi}\\0.001&\text{milli}\\0.000001&\text{micro}\\\vdots&\vdots\\\end{array}\right.$

And thus 0.000001 of something is a micro-something (i.e. one millionth of a certain unit)

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=p%5E%7B2%7Dxp%5E%7B2%7D" id="TexFormula1" title="p^{2}xp^{2}" alt="p^{2}xp^{2}" align="absmidd

vichka [17]

Answer:

${p}^{4} x$

Step-by-step explanation:

1) Regroup terms.

${p}^{2} p^{2} x$

2) Use product rule.

${p}^{2 + 2} x$

3) Simplify 2 × 2 to 4.

$p ^{4} x$

Therefor, the answer is p⁴x

5 0

2 years ago

Read 2 more answers

The vertices of ΔABC are A(−3,4), B(−2,4), and C(−5,2). If ΔABC is reflected across the line y=−2 to produce the image ΔA'B'C

Mumz [18]

The coordinates of vertex B' is $P'(x,y) = (-2, -8)$ .

<h3>How to calculate the coordinate of point by reflection</h3>

A point if reflected across the line $y = -2$ by means of the following formula:

$P'(x,y) = P(x,y)+2\cdot [(x_{P}, -2)-P(x,y)]$ (1)

Where:

$P(x,y)$ - Original point
$x_{P}$ - x-Coordinate of point P
$P'(x,y)$ - Resulting point

If we know that $P(x,y) = (-2,4)$ and $x_{P} = -2$ , then the coordinates of the vertex is:

$P'(x,y) = (-2, 4) + 2\cdot [(-2,-2)-(-2,4)]$

$P'(x,y) = (-2, 4) +2\cdot (0, -6)$

$P'(x,y) = (-2, 4) + (0,-12)$

$P'(x,y) = (-2, -8)$

The coordinates of vertex B' is $P'(x,y) = (-2, -8)$ . $\blacksquare$

To learn more on reflections, we kindly invite to check this verified question: brainly.com/question/1878272

3 0

2 years ago

How do I figure this one out?

Inessa [10]

9k2-12k+4

(k2-6k)+(-6k+4) factor out the 3k from 9k2 0 6k: 3k(k-2) factor out -2 from -6k +4n: -2 (3k-2) factor out common term (3k-2) = (3k-2 ) (3k-2) that equals (3k-2)2

5 0

3 years ago

Factor the GCF: 21x3y4 + 15x2y2 − 12xy3.

-Dominant- [34]

Ugh, these questions.

21x^3y^4 + 15x^2y^2 - 12xy^3

3xy^2 (7x^2y^2 + 5x - 4y)

Clearing up clutter...

3xy² (7x²y² + 5x - 4y)

That's your answer. Thanks for working my brain. ;)

6 0

3 years ago

Read 2 more answers