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3 years ago

Define p ~ q by the equation p ~ q = p^2q^3-3q. Then 2 ~ 3=

Mathematics

1 answer:

son4ous [18]3 years ago

5 0

Does it have something to do with congruency?

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Find the least common denominator (lcd) of 1/3 and 2/9 .

OLEGan [10]

The lowest common denominator of 1/3 and 2/9 = 9

8 0

3 years ago

-3x(x+8)+x+2(9-x-x^2) please show solving steps

Flauer [41]

Answer:

-5x^2 - 25x + 18

Step-by-step explanation:

-3x ( x + 8 ) + x + 2 ( 9 - x - x^2 ) ( original equation )

-3x^2 - 24x + x + 18 - 2x - 2x^2 ( distribute )

-3x^2 - 2x^2 - 24x + x - 2x + 18 ( order them based on the variables . )

( -3x^2 - 2x^2 ) (- 24x + x - 2x ) ( + 18 ) ( just separated them not a part of solving !! )

-5x^2 - 25x + 18 ( solved , and the answer :) )

Hope its helps !!!

4 0

3 years ago

Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!

forsale [732]

$1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}$

Step-by-step explanation:

The given equation is $4x^{2}-8x-1$

Let $a$ be the coefficient of $x^{2}$

Let $b$ be the coefficient of $x$

Let $c$ be the constant.

Then the roots α,β for the equation $ax^{2}+bx+c$ are $\dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}$

So,α= $\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}$

β= $\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}$ .

So the roots are $1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}$

5 0

3 years ago

Can somebody help me plz with this math problem!!

Tema [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Acre Middle School spent $1443.20 on 55 math books. How many did each book cost

ollegr [7]

Each book costs $26.24 because 1443.20÷55=26.24

3 0

4 years ago