How do you find the value of x
2 answers:
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3x-2y=6
1) <span>Add -3x to both sides.
</span><span><span> 3x</span>−<span>2y</span></span>=<span>6
</span>+3x +3x
-----------------
<span>−<span>2y</span></span>=<span><span>−<span>3x</span></span>+<span>6
</span></span><span>
2) Divide both sides by -2.
</span>
= 
y=<span><span><span>32</span>x</span>−<span>3
</span></span>
3) Substitute the y with the equation
3x-2(32x-3)=6
3x-64x+6=6
4) Combine like terms
3x-64x+6=6
-61x+6=6
5) Subtract 6 from each side of the equation
-61x+6=6
-6 -6 (+6-5 gets crossed out)
--------------
-61x=0
6) Divide both sides by -61
x=0
============================================================
Now that you've got you x intercept, use the x value and substitute it into the
y=32x−3
y=32(0)-3
y=0-3
y=-3
(0,-3)
1) <span>Add -3x to both sides.
</span><span><span> 3x</span>−<span>2y</span></span>=<span>6
</span>+3x +3x
-----------------
<span>−<span>2y</span></span>=<span><span>−<span>3x</span></span>+<span>6
</span></span><span>
2) Divide both sides by -2.
</span>
y=<span><span><span>32</span>x</span>−<span>3
</span></span>
3) Substitute the y with the equation
3x-2(32x-3)=6
3x-64x+6=6
4) Combine like terms
3x-64x+6=6
-61x+6=6
5) Subtract 6 from each side of the equation
-61x+6=6
-6 -6 (+6-5 gets crossed out)
--------------
-61x=0
6) Divide both sides by -61
x=0
============================================================
Now that you've got you x intercept, use the x value and substitute it into the
y=32x−3
y=32(0)-3
y=0-3
y=-3
(0,-3)
As far as I can tell, is referring and assuming the ruler doesn't have any fractional values, namely it only has markings with integers.
so in short is asking, what are the two integers that the fractional 5¼ is between?
so in short is asking, what are the two integers that the fractional 5¼ is between?