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3 years ago

5x + 5 = x + 45 PLEASE HELP

1 answer:

5 0

$5x+5=x+45$

We'd rather not have x on both sides of the equation when trying to solve this. To eliminate the x on the right side, subtract both sides by x.

$5x+5-x=x+45-x$
$4x+5=45$

Let's get eliminate the "5" on the left side. Subtract both sides by 5.

$4x+5-5=45-5$
$4x=40$

To finish this, divide both sides by 4.

$4x \div 4=40 \div 4$
$x=10$

That is the answer. Hope this helps! :)

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Example 4

Vesnalui [34]

Answer: Part a: b represents the base fee charged for the "house call" job

m is the hourly rate.

x is the number of hours at the job.

y represents the total cost for the job.

Part b:. The y-intercept is 65

The equation follows y=mx+b

Y= 42x + 65

Part c:. $275

Step-by-step explanation:

The difference between the two total costs, (Camilla 191 - Connor 107)

= $84. That is the rise. The run is the difference in time, 2 hours. 84/2 = 42.

m= 42

42 from 107 to find b, the base fee, 65 This is the y-intercept.

The equation is y= 42x + 65

Quick check using Camilla's bill: 191 = (42)(3) + 65

191 = 126 + 65 True!

Part C:

To find the total cost of the plumber's 5 hour job,

Y = 42(5) + 65

Y= 210 + 65

Y= $275

7 0

2 years ago

30 out of 600=____ %

sasho [114]

Step-by-step explanation:

let % be X

30 = x% of 600

30 = x × 600 / 100

x = 30 × 100 /60

x = 5

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3 0

2 years ago

Mary has rehearsed her ballet solo for five and a half hours. A week from now, she wants to have rehearsed at least a total of n

tensa zangetsu [6.8K]

She has to rehearse at least 2 hours a day

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2 years ago

stack of mail consists of 8 bills, 10 letters, and 6 advertisements. One piece of mail is drawn at random and put aside. Then a

kozerog [31]

INFORMATION:

We know that:

- stack of mail consists of 8 bills, 10 letters, and 6 advertisements.

- One piece of mail is drawn at random and put aside. Then a second piece of mail is drawn.

And we must find P (both are letters)

STEP BY STEP EXPLANATION:

To find the probability, we need to know that we have two events. First, when one piece of mail is drawn at random and put aside and, second, when a second piece of mail is drawn.

These two events are dependent. If A and B are dependent events, P(A and B) = P(A) • P(B after A) where P(B after A) is the probability that B occurs after A has occurred.

So, first

- Probability of A (the first piece is letter)

$P(A)=\frac{favorable\text{ }cases}{total\text{ cases}}=\frac{10}{24}$

- Probability of B after A

Since A already occurred and one piece of the mail was drawn (a letter), now in total we would have 9 letter and 23 total pieces

$P(B\text{ after }A)=\frac{9}{23}$

Finally, replacing in the initial formula

$P(A\text{ and }B)=\frac{10}{24}\cdot\frac{9}{23}=\frac{90}{552}=0.1630$

Finally, the probability would be 0.1630

ANSWER:

P (both are letters) = 0.1630

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