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gizmo_the_mogwai [7]
3 years ago
11

PlSSS HELP IF YOU TURLY KNOW THISS

Mathematics
1 answer:
o-na [289]3 years ago
8 0

Answer:

x=3  hope this helps

Step-by-step explanation:

You might be interested in
Guys!! anyone can help me solve this geometry problem?<br>What is the area of this triangle?
NeX [460]

Answer:

10657.5

Step-by-step explanation:

<h2>Long way that is unnecessarily long</h2>

We can start by finding the area of the larger triangle. Using the Pythagorean theorem, we can say that 251²-105²=the bottom side², and  251²-105²=51976, so the bottom side of the larger triangle is √51976 , or approximately 228. Then, the area of the larger triangle is √51976 * 105/2 = 11969 (approximately). Then, the area of the smallest triangle (the largest triangle - the one that we're trying to find the area of) is 105*(√51976-203)/2 = approximately 1312. Then, subtracting that from the total area, we get (√51976 * 105 -  105*(√51976-203))/2 = 105*203/2 = 10657.5

<h2>Short way</h2>

ALTERNATIVELY, upon further review, we can just see that the height is 105 and the base is 203, so we multiply those two and divide by 2, as is the formula for the area of a triangle, to get 10657.5

3 0
3 years ago
00:00
Zigmanuir [339]

Answer:

c   and d

Step-by-step explanation:

i think

4 0
3 years ago
Read 2 more answers
Omgggg helppp I need this now plss
Maurinko [17]

Answer:

-4,-4

Step-by-step explanation:

5 0
3 years ago
Find a negative angle that is co-terminal with the angle 158.3
jenyasd209 [6]

Answer:0.0

Step-by-step explanation:

4 0
3 years ago
How to bring the polynomial to the standard form p(x) x^2-2x+4) (x^2+2x+4) ​
saveliy_v [14]
<h3>Solution:</h3>

\rightarrow\sf((p(x) {x}^{2}  + 2x + 4)( {x}^{2}  + 2x + 4)) \\  = \sf  {ax}^{2}  + bx + c \\  = \sf(p(x) {x}^{2}  {x}^{2}  + p(x) {x}^{2} (2x) + p(x) {x}^{2}  \times 4 + 2x \times  {x}^{2}  + 2x(2x) + 2x \times 4 +  {4x}^{2}  + 4(2x) + 4 \times 4) \\  = \sf( {x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16) \\   \rightarrow \large\boxed{\sf\red{{{x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16}}}

<h3>Answer:</h3>

\large\boxed{\sf{\red{{x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16}}}

\color{red}{==========================}

✍︎ꕥᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴꕥ

✍︎ꕥᴄᴀʀʀʏᴏɴʟᴇᴀʀɴɪɴɢꕥ

✍︎ꕥᴋɪᴍ ᴀʀᴀꕥ

5 0
2 years ago
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