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trapecia [35]
3 years ago
11

Help on this one as well

Mathematics
1 answer:
SashulF [63]3 years ago
8 0
The answer is 6.375 hope it help
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torisob [31]

Answer:

3) yes, it is in the shaded region

4) no, it lies on a less-than line

5) yes, it lies on a greater-than-or-equal-to line

6) no, it isnt in the shaded region

Step-by-step explanation:

6 0
3 years ago
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Round 62.276 to the nearest hundredth
AnnZ [28]

Answer:

62.28

Step-by-step explanation:

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3 years ago
Geometry <br> help please
dexar [7]

The angle m∠UVW can be found using angle of circumference rule in geometry. Therefore, m∠UVW = 67°

<h3 /><h3>Angle on a circumference</h3>

An angle at the circumference of a circle is half the angle at the centre standing on the same arc.

In other words, the angle at the centre of a circle is twice the angle at the circumference.

Therefore,

m∠UVW = 134 / 2

m∠UVW = 67 degrees

learn more on geometry here; brainly.com/question/16836055

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5 0
2 years ago
Heidikae reads 420 pages a week. In the summer, she reads 17% less. Approximately how many pages per week does she read in the s
Marat540 [252]
420-17%= 348.6



This is it because she read 420 pages during the summer but then she reads 17% less which is subtracting then get the answer which is 348.6
8 0
3 years ago
surveyor stands 100 m from the base of a tower on which an antenna stands. He measures the angles of elevation to the top and bo
balu736 [363]

Answer: 36.3m

Step-by-step explanation:

To solve this, we can draw two triangle rectangles, where the distance between the man and the base of the tower is one of the cathetus, the adjacent one, the height will be the opposite cathetus.

The triangle where the elevation angle is 58° is associated with the height of the tower without the aerial

The other triangle, where the elevation angle is 63° is associated with the height of the tower with the aerial.

Then we can calculate those two heights, then compute the difference, and the difference will be equal to the height of the aerial.

In both cases we want to calculate the opposite cathetus, then we should use the relation:

Tan(θ) = (Op. cath)/(Adj. cath)

The height without the aerial is h1, let's find it:

Tan(58°) = h1/100m

Tan(58°)*100m = h1 = 160m.

The height with the aerial is h2, let's find it:

Tan(63°) = h2/100m

Tan(63°)*100m = h2 = 196.3m

Then the height of the aerial will be:

h2 - h1 =  196.3m -  160m = 36.3m

6 0
3 years ago
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