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AleksAgata [21]
3 years ago
13

Given the system y=2x+2 and y=2x^2, which statement below is true?

Mathematics
1 answer:
Gwar [14]3 years ago
3 0
I don't see "below"   
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-5x+1+2x+2=-2+2x<br> I’m super lost
DaniilM [7]
Are you trying to simplify the equation? if so, combine the like terms on each side first. -3x + 3 = -2 + 2x. Then simplify, -5x = -5. And solve, x = 1
3 0
3 years ago
6x-7y= -2 please help me
Nana76 [90]

Answer:

X=7/6y+-1/3

Step-by-step explanation:

It will be hard for me to demonstrate the equation

6 0
3 years ago
An equilateral triangle has what type of symmetry?
blondinia [14]

Answer:

An equilateral triangle has 3 lines of symmetry

Hope this helps

Step-by-step explanation:

7 0
3 years ago
Solve in attachment....​
olga2289 [7]

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

\displaystyle  \int_{0} ^{1} 5x \sqrt{x} dx

use constant integration rule which yields:

\displaystyle  5\int_{0} ^{1} x \sqrt{x} dx

notice that we can rewrite √x using Law of exponent therefore we obtain:

\displaystyle  5\int_{0} ^{1} x \cdot  {x}^{1/2} dx

once again use law of exponent which yields:

\displaystyle  5\int_{0} ^{1}  {x}^{ \frac{3}{2} } dx

use exponent integration rule which yields;

\displaystyle  5 \left( \frac{{x}^{ \frac{3}{2}  + 1  } }{ \frac{3}{2}  + 1} \right)  \bigg|  _{0} ^{1}

simplify which yields:

\displaystyle  2 {x}^{2}  \sqrt{x}   \bigg|  _{0} ^{1}

recall fundamental theorem:

\displaystyle  2 (  {1}^{2}) (\sqrt{1}  ) - 2( {0}^{2} )( \sqrt{0)}

simplify:

\displaystyle  2

hence

our answer is A

8 0
2 years ago
Read 2 more answers
PLEASE HELP SO I CAN PASS MY TEST
Brums [2.3K]

Answer:

10

Step-by-step explanation:

The first thing to do would be to find how many 1/4 cups are in the 1 cup. Divide 1 by 1/4 and you'd get 4.

Just multiply 2 1/2 by 4 and you get 10

8 0
3 years ago
Read 2 more answers
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