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alekssr [168]
3 years ago
6

A blackjack is a 10-point card and an ace for a value of 21. Use your answers to parts (a), (b), and (c) to determine the probab

ility that a player is dealt blackjack. (Hint: Part (d) is not a hypergeometric problem. Develop your own logical relationship as to how the hypergeometric probabilities from parts (a), (b), and (c) can be combined to answer this question.)
Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

Results:

0.1432

0.0045

0.0905

0.0483

Step-by-step explanation:

Step a:

P(A or 10, A or 10) = 20/52 * 19/51 = 5/13 / 19/51 = 95/663 = 0.1432

Step b:

P(A A) = 4/52 * 3/51 = 1/13 * 1/17 = 1/221 = 0.0045

Step c:

P(10 10) = 16/52 * 15/51 = 4/13 * 5/17 = 20/221 = 0.0905

Step d:

P(A 10 or 10 A) = 2 * 4/52 * 16/51 = 2/13 * 16/51 = 32/663 = 0.0483

As well we get the probability by subtracting a,  b and c:  

P(blackjack): 0.1432 - 0.0905 - 0.0045 = 0.0482  

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Jeff was counting the squirrels and birds in the park. He counted 16 heads and 44 legs. How many birds did Jeff count?
hodyreva [135]
So 1 head per squirel and 1 head per bird
4 legs per squirel and 2 legs per bird
s=number of squirels
b=birds
the equatinos should be
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simplify the second equaiton by divideinb by 2
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divide 2
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b+s=16
and
b+2s=22
we can actually add the two equations together with the first one made negative
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0b+1s=6
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subsitute
b+s=16
b+6=16
subtract 6 from both sides
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