Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
This question is incomplete. The options are:
<span>a. be choosy about which females they mate with.
b. be indiscriminant about which females they mate with.
c. mate with as many females as possible.
d. compete to mate with choosy females.
</span>
The answer is a: be choosy about which females they mate with.
This is because the male would in this case be investing a lot of energy in parenting its young, and would therefore adopt a strategy of mating with one or very few females. It therefore makes sense that the male would be choosy in regards to its mate.
Answer: Amoeba are living even though they have one cell
Explanation:
<span>The
interaction of motor proteins such as dynein, is responsible for the movement
of organelles in cells which uses energy to move parts of the cytoskeleton. Cytoskeleton is a network of intermediate
filaments, microtubules and microfilaments that outspread throughout the
cytoplasm and serve a variety of signaling, transport and mechanical functions.</span>
