Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
The only way for gases to diffuse in and out of the leaf is through small openings on the bottom of the leaf, the stomata.
Answer:
Girl bye
Explanation:do your work
Oh gagahahs and the hormymoneya re better because I am wasting your trip ma
Answer:
A haploid is a cell with a single set of chromosomes.