the answer is 5 car / hr.........................................
Answer:
a. 
Step-by-step explanation:
The given vector is v= 4i - 5j
The magnitude of this vector is;



The unit vector u in the direction of v is;



We rationalize to get

For the answer to the question above, <span>
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>
Here are the steps
1: Put the compass on Q and make the width equal to the distance from Q to L. Extend line LM towards the left side of L and draw an arc hitting the line segment on the left side of L
2. <span> Without changing the width and position of the compass, draw an arc between L and M.
3. Without changing the width of the compass, put the compass on the point of intersection of the arc and line LM (left side of L). Draw an arc above line LM.
4. Without changing the width of the compass, put the compass on the point of intersection of the arc and line LM (right side of L). Draw an arc above line LM.
5. Use a straight edge to make a line from the intersection of the two arcs above line LM to Q intersecting through L along the way. </span>
Answer: temperature and weight
Step-by-step explanation: Temperature can increase or decrease/can go up and down without moving. The same goes with weight, it can go up or down without moving.