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3 years ago

I NEED HELP WILL GIVE BRAINLIEST. PLZZZZ

Mathematics

2 answers:

Ilya [14]3 years ago

6 0

First option tho!! Is the right answer

ollegr [7]3 years ago

3 0

The first option is correct !!!!!

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Evaluate 23x-1 for x = 1.<br> 1<br> 4<br> 7<br> 8

denis23 [38]

If x is 1, then 23x is 23, so we have 23-1=22 as the answer.

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4 years ago

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The measure of an angle is 53°. What is the measure of its supplementary angle?

viktelen [127]

Answer:

127

Step-by-step explanation:

if it is supplementary it =180

if it is complimentary it =90

so 180-53= 127

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3 years ago

The following are all angle measures (in degrees, rounded to the nearest tenth) whose tangent is 2.62.62, point, 6. Which is the

GalinKa [24]

Answer:

I'm not fully sure but id say the principle value would be choice C

Step-by-step explanation:

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3 years ago

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A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. When he started his diet, he weighed

Damm [24]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x ----> represent the number of months

y ----> represent the sumo wrestler's weight

we know that

The linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value

In this problem we have

The slope is equal to $m=5.5\ kg\ per\ month$

The y-intercept is equal to $b=79.5\ kg$

substitute

$y=5.5x+79.5$

using a graphing tool

The graph in the attached figure

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3 years ago

If cosh x = 13 5 and x > 0, find the values of the other hyperbolic functions at x.

givi [52]

Recall that

$\cosh^2x-\sinh^2x=1\implies \cosh x=\pm\sqrt{1+\sinh^2x}$

You're given that $\cosh x=\dfrac{13}5>0$ , so omit the negative root. Then

$\dfrac{13}5=\sqrt{1+\sinh^2x}\implies\sinh^2x=\dfrac{144}{25}\implies\sinh x=\pm\dfrac{12}5$

Because $x>0$ , you have $\sinh x>0$ too, so omit the negative root again. Then $\sinh x=\dfrac{12}5$ .

Now,

$\mbox{sech }x=\dfrac1{\cosh x}=\dfrac5{13}$
$\mbox{csch }x=\dfrac1{\sinh x}=\dfrac5{12}$
$\tanh x=\dfrac{\sinh x}{\cosh x}=\dfrac{\frac{12}5}{\frac{13}5}=\dfrac{12}{13}$
$\coth x=\dfrac1{\tanh x}=\dfrac{13}{12}$

7 0

3 years ago