Answer:
The value of is equal to 
Step-by-step explanation:
we know that
-----> by alternate exterior angles
solve for k
Answer:
<h2>2.6</h2>
Step-by-step explanation:
To solve this, we need to use the Pythagorean theorem to solve this.
The way to solve is by solving for AD by using triangle CAD and then using that result to solve for BD.
3.4² + b² = 6.5²
11.56 + b² = 42.25
42.25 - 11.56 = b²
b = √30.69
b = 5.53985559 or about 5.5
4.9² + b² = 5.5²
24.01 + b² = 30.69
30.69 - 24.01 = 6.68
b = √6.68
b = 2.58456959666 or about 2.6
<h2>EDIT: the other user is incorrect, here's why</h2>
3.4 + 4.5 = 7.9
6.5² + 4.9² = 7.9²
66.26 doesn't equal 62.41
Answer:
Math:9.75
Science:6
Step-by-step explanation:
Not 100% sure on those answers but here is hot to figure the problem out:
A point that falls outside the data set's inner fences is classified as a minor outlier, while one that falls outside the outer fences is classified as a major outlier. To find the inner fences for your data set, first, multiply the interquartile range by 1.5. Then, add the result to Q3 and subtract it from Q1.
The temperature was -14°F at 8 a.m.
At noon is was 10 degrees warmer - the temperature increase was 10°F
-14°F + 10°F = -4°F
The tempertaure increase between noon and 4 p.m. was twice the previous increase in temperature, which was 10°F.
10°F x 2 = 20°F
We want to know the temperature at 4 p.m. so we just add it up to the previous result.
-4°F + 20°F = 16°F
16°F is the correct answer
Answer:
See Explanation
Step-by-step explanation:
Given
--- Number of tryouts
Required
Determine the average distance
<em>This question has missing details, as the distance he hits the ball in each tryout is not given. However, I'll give a general explanation.</em>
<em></em>
The mean is calculated as:
means the sum of the distance in each tryout.
Assume that the distance in the 10 tryouts are: 
So, the mean is:
<em>So, the average distance is 6.5</em>
