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3 years ago

If a^2 + b^2 =15 and ab=3 , then what is the value of (a-b)^2 ?

Mathematics

1 answer:

katen-ka-za [31]3 years ago

7 0

$\bf (a-b)^2\implies a^2-2ab+b^2\implies \boxed{a^2+b^2}-2ab\implies \boxed{15}-2(3)$

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stiks02 [169]

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3 years ago

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ycow [4]

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Step-by-step explanation:

We must solve the following rational equation:

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Now we present the procedure:

1) $\frac{x}{2} = \frac{x^{2}}{x-2}$ Given

2) $x\cdot (x-2) = 2\cdot x^{2}$ Compatibility with multiplication/Existence of the multiplicative inverse/Definition of division/Modulative property.

3) $x^{2}-2\cdot x = 2\cdot x^{2}$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

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Now we check the rational equation with each root:

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$0 = 0$

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3 years ago

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vladimir1956 [14]

Answer:

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Since its a circle, it will be 360 degrees, so then do 190+26=206, then do 360-206=154

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3 years ago