All categories

1 year ago

Think About the Process The length of a rectangle is twice the width. The area of the rectangle

Mathematics

1 answer:

natima [27]1 year ago

8 0

Answer:

length of each square= $\sqrt{43}$ ≈ 6.6

the length of the rectangle = 2 $\sqrt{43}$ ≈ 13.1

width of the rectangle ≈ $\sqrt{43}$ ≈ 6.6

Step-by-step explanation:

You might be interested in

Write an algebraic expression for: the quantity 2 plus 88y divided by 47

Mnenie [13.5K]

Write and algebraic expression for the quantity 2 plus 88y divided by 47. Your answer would be D.
Answer: D. 2+88y/47

7 0

2 years ago

What is the measure of the missing side to the nearest tenth?<br> 9<br> 23<br> х

Fynjy0 [20]

Answer: 24.7

Step-by-step explanation:

3 0

2 years ago

Two neighbors, wilma and betty, each have a swimming pool. both wilma's and betty's pools hold 9900 gallons of water. if wilma's

s2008m [1.1K]

To solve this problem we will start by calculating time needed for each of them to fill the pool.

We have formula:
Volume = rate * time
Or
time = volume / rate

Wilma:
time = 9900 / 900
time = 11h

Betty:
time = 9900 / 500
time = 19.8h

Now we substract these two numbers:
time_difference = 19.8 - 11 = 8.8h

Betty needs 8.8 hours more than Wilma to fill the pool.

3 0

2 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

2 years ago

Priscilla is on her school’s swim team. Her coach has noted the number of laps Priscilla and five of her teammates can swim with

ruslelena [56]

Answer:

Mean: 5, Median: 5, Mode: 5, Range: 4

Step-by-step explanation:

Mean: 5

5 + 4 + 6 + 3 + 7 + 5 = 30

30/6 = 5

Median: 5

3, 4, 5, 5, 6, 7,

Mode: 5

3, 4, 5, 5, 6, 7

2 fives

Range: 4

7 - 3 = 4

5 0

1 year ago