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ale4655 [162]
3 years ago
14

How does the difference between fe and fo influence the outcome of a chi-square test?​?

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0
The larger the difference, the larger the value of Chi2 and the greater the likelihood of rejecting the null hypothesis.
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Work out the shaded area​
Dennis_Churaev [7]

Answer:

<h2> 70 {cm}^{2}</h2>

Step-by-step explanation:

Shaded area:

Area of big rectangle - Area of small rectangle

= 10 \times 12 - (10 - 5) \times (12 - 2)

Calculate the difference

= 10  \times 12 - 5 \times 10

Calculate the product

= 120 - 50

Calculate the difference

= 70 \:  {cm}^{2}

Hope this helps...

Best regards!!

7 0
3 years ago
How much glass is needed to manufacture 1000 paperweights
Bumek [7]
Your answer should be 1200 inches cubed
8 0
3 years ago
Use the discriminant to determine how many real number solutions exist for the quadratic equations -4j+3j-28=0
aleksandr82 [10.1K]
<span>the correct equation is
- 4j² + 3j - 28 =0

 ax² + bx + c,
 a = -4, b=3  c =- 28.
The discriminent D = b² - 4.a.cD = 3² - 4(-4)(-28)D = -439 
If D ≥ 0 there are either 2 roots or one double if = 0)if D< 0, there are no real roots (but 2 imaginary roots)Since D < 0, then there is no real roots
 The answer there is no real roots</span>
8 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
To solve 5/7 - 2/n = 1/21
Usimov [2.4K]

Answer:

the answer is n=3

Step-by-step explanation:

3 0
3 years ago
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