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lidiya [134]
3 years ago
12

A college statistics class conducted a survey of how students spend their money. They asked 25 students to estimate how much mon

ey they typically spend each week on fast food. They determined that the mean amount spent on fast food each week is $31.52 and the median is $32. Later they realized that a value entered as $2 should have been $20. They recalculate the mean and the median. Which of the following is true? Group of answer choices
a. The mean and median will increase.
b. The mean will increase, but the median will remain the same.
c. The mean will stay the same, but the median will increase.
d. Both the mean and median will remain the same.
Mathematics
1 answer:
anastassius [24]3 years ago
7 0

Answer:

Option B, The mean will increase, but the median will remain the same.

Step-by-step explanation:

Given

Mean value is  31.52 dollars

Median Value is 32 dollar.

Mean is the average of all the units in a given set of data. Change in any of the number will change the mean.

Here the mean is 31.25

Total money would be 31.25 * 25 = 781.25\\

A number is changed from 2 to 20 , i.e addition of 18 dollars

the new mean would be 781.25 + 18/25 = 31.97

However, the median value is the value of the unit at the center of the arrangement. Hence, it will not change.

Option B is correct

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A school ice hockey game has three 20-minute periods. Collin plays 12 minutes each period. Which ratio represents Collin's playi
Korvikt [17]

Answer: 36:60


Step-by-step explanation:

3x20=60,3x12=36

3 0
3 years ago
Someone know how to do this?: 6x2+18x=0
Crazy boy [7]
The answer to the question is: Yes.

Explanation:  It can be solved by following exactly the same procedures
that solved the other two questions that you posted within the past 15 minutes.

Since I'm here already, here is the solution to this one:

6x² + 18x = 0

Divide each side of the equation by 6 :

x² + 3x = 0

Factor the left side:

x(x+ 3) = 0

This statement is true if x=0 or if x=3.

The solution to this one is even the same as the solution to the last one you posted.
You really ought to take a break, go back, review the solutions you've been given,
and try to solve a few on your own.
4 0
3 years ago
Its 1:35 what time it will be in 40 mins?
gulaghasi [49]
2:15 hope it helps your welcome
6 0
3 years ago
Read 2 more answers
What is the domain and derivative of f(x)=ln(2xsqrt(2+x))?
wolverine [178]
For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining 
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
5 0
3 years ago
The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among
jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let <em>X</em> = number of households watching the show.

The probability of the random variable <em>x</em> is, P (X) = <em>p</em> = 0.18.

The sample selected for the survey is of size, <em>n</em> = 14

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 14 and <em>p</em> = 0.18.

The probability of a Binomial distribution is computed using the formula:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-0.062\\=0.938

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0
4 years ago
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