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Katarina [22]
3 years ago
12

A line segment on a number line has its endpoints at -9 and 6. Find the coordinate of the midpoint of the segment.. . A. 1.5. *

B. -1.5. C. 2. D. -3. . Find the coordinates of the midpoint of HX given that H(-1,3) and X(7,-1).. . A. (3,1). * B. (0,4). C. (-3,1). D. (-4,0). . please help!
Mathematics
2 answers:
Lyrx [107]3 years ago
4 0
By definition, the midpoint is given by:
 m =  (\frac{x1+x2}{2},  \frac{y1+y2}{2})

 Part A:
 For the line segment we have:
 m =  \frac{-9+6}{2}
 m=  \frac{-3}{2}
 m = -1.5
 Answer:
 
the coordinate of the midpoint of the segment is:
 
B. -1.5

 
Part B:
 
For line segment HX we have:
 m = (\frac{-1+7}{2}, \frac{3-1}{2})
 m = (\frac{6}{2}, \frac{2}{2})
 m = (3,1)
 Answer:
 
the coordinates of the midpoint of the segment is:
 
A. (3,1)
Ivan3 years ago
4 0
Add

-9 + 6 = -3 
Divide by 2

-1.5

2)  -1 + 7 = 6 / 2 = 3 ;  3 + -1 = 2 / 2 = 1

(3, 1)

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Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
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So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
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2x   - 3y  +  z = 0

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- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

Now solve the equation accordingly:

\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}

Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

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