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4 years ago

7

Cecilia ordered 5 pizza for a group of friends. Each pizza had 8 slices. All but 3 slices were eaten. How many slices were eaten

?

1 answer:

UkoKoshka [18]4 years ago

3 0

Answer:

37 (hope this helps :)

Step-by-step explanation:

8 slices per pizza

5 pizzas

8 * 5 = 40

40 - 3 = 37

37 slices of pizza were eaten. and 3 slices were not eaten

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19 ≥ 3f+1 ≥5 pls help

Juliette [100K]

Answer:

Hi...u should do like this

18>3f>4

6>f>4/3

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3 years ago

A submarine sandwich 1.5 feet long is cut into 0.25 pieces. how many pieces will there be

ale4655 [162]

There would be 1.75 pieces

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4 years ago

What are the domain and range of this function?

RUDIKE [14]

<h3>Answer: Choice D</h3>

Domain: all real numbers
Range: $y \ge 1$

===========================================

Explanation:

The domain is the set of allowed x inputs. We can plug in any x value we want as the graph stretches on forever to the left and to the right. There aren't any division by zero errors or any issues like that to worry about, so that's why we don't kick out any x values from the domain.

The domain being all real numbers translates to the interval notation $(-\infty, \infty)$ which is basically saying $-\infty < x < \infty$

-----------------------------------

The range is the set of y outputs possible. The graph shows that y = 1 is the smallest y output, so y = 1 or y can be greater than this.

In short, $y \ge 1$ is the range which converts to the interval notation $[1, \infty)$ which is the same as saying $1 \le y < \infty$

-----------------------------------

Extra info:

The equation of this absolute value function is y = |x|+1

8 0

3 years ago

Find the nth degree polynomial function with real coefficients satisfying the given conditions.

RUDIKE [14]

$\bf (x+1)(x-3)(x-2-4i)(x-2+4i)
\\\\
\textit{now, let's take a peek at }(x-2-4i)(x-2+4i)\\
\textit{and recall our }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x-2-4i)(x-2+4i)\implies [(x-2)-(4i)][(x-2)+(4i)]
\\\\\
[(x-2)^2-(4i)^2]\implies [(x^2-2x+4)-(4^2\boxed{i^2})]
\\\\\
[(x^2-2x+4)-(16\cdot \boxed{-1})]\implies [(x^2-2x+4)+16]
\\\\
(x^2-2x+20)\\\\
-----------------------------$

$\bf thus
\\\\

\begin{array}{llll}
(x+1)(x-3)\\(x-2-4i)(x-2+4i)
\end{array}\implies (x+1)(x-3)(x^2-2x+20)
\\\\\\
(x^2-2x-3)(x^2-2x+20)\implies 
\begin{array}{llll}
x^4-2x^3+20x^2-2x^3\\+4x^2-40x+3x^2-6x+60
\end{array}
\\\\\\
x^4-4x^3+27x^2-46x+60$

4 0

3 years ago

The braking distance, D, of a car is directly proportional to the square of its speed, v. When d=5, v=10

Ivenika [448]

Answer:

<h2> d = 245</h2>

Step-by-step explanation:

d is directly proportional to the square of a speed v

d = av²

5 = a•10²

5 = 100a

a = 0.05

d = 0.05v²

d = 0.05•70²

d = 0.05•4900

d = 245

5 0

3 years ago