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Sergeeva-Olga [200]
3 years ago
12

a metal worker has a metal alloy that is 20% copper, and another metal alloy that is 60% copper. How many kilograms (kg) of each

allow should the metal worker combine to create 80kg of aa 52% copper alloy?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
5 0

Let X = the 29% alloy and Y = the 60% alloy.

They want a total of 80kg, so you have X +Y = 80

Rewrite that to get X = 80-Y


You also want 0.20X + 0.60Y = 0.52(80)

Replace X with 80-y:

0.20(80-y) + 0.60y = 0.52(80)

Simplify:

16 - 0.20y + 0.60y = 41.6

Combine like terms:

16 +0.40y = 41.6

Subtract 16 from each side:

0.40y = 25.6

Divide both sides by 0.40

y = 25.6 / 0.40

y = 64


Now you have Y replace y with 80 in X = 80-Y

X = 80 - 64

X = 16

They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.


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butalik [34]

ANSWER

10C_5(2)^{5}( - 3)^5

EXPLANATION

The given binomial expansion is:

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Hence the coefficient is;

10C_5(2)^{5}( - 3)^5

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Lets start by using a formula (don't remember the name) 

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