Given:
Consider the below figure attached with this question.
∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°
To find:
The measure of ∠EFH.
Solution:
From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,



Isolate variable terms.


Divide both sides by 13.


The value of x is 4.




Therefore, the measure of ∠EFH is 21°.
I think that would be 9 I am not sure.
Answer:
7x³y² - 3x²y² + xy - 5
Step-by-step explanation:
Add like terms.
5x³y² + 2x³y² = 7x³y²
-3x²y² = -3x²y²
-3xy + 4xy = xy
2 - 7 = -5
Put them all together.
7x³y² - 3x²y² + xy - 5
Answer:
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Step-by-step explanation: