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galina1969 [7]
3 years ago
10

The number 7 is what percent of 80

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
3 0

Answer:

5.6

Step-by-step explanation:because if you divide correctly it will equal 5.6

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Jordan will hike the trail shown at a rate of 4 ​mi/h. Write a linear equation to represent the distance Jordan still has to wal
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Y=25-4x

Y means the distance Jordan still has to walk after x hour

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3 years ago
Please answer this Yall
lora16 [44]
I believe the answer would be b^4.

Explanation:
Use Quotient Rule: x^a/x^b=x^a-b
b^10-6

Then Simplify 10-6 to 4
b^4
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WebAssign will do simple calculations for you, using , -, *, /, parentheses, and e-notation. For example, if a question asks for
kondor19780726 [428]

Answer:

10800

Step-by-step explanation:

To solve any equation we use PEDMAS rule(this is the sequence of priorities) where:

P: Parentheses

E: Exponent

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120\times 90=10800

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3 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
4 years ago
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vichka [17]

Answer:

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