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vichka [17]
3 years ago
15

Show how to count from 170 to 410 using tens and hundreds

Mathematics
2 answers:
slava [35]3 years ago
8 0
170 + 100=270
270 +100=370
370+10=380
380+10=390
390+10 =400
400+ 10=410
we started from 170 and ended at 410 by adding tens and hundreds.
forsale [732]3 years ago
7 0
In order to count from 170 to 410 using tens and hundreds, we first need to start adding 100 to 170 as long as the number is less than 410 as shown below:

170 + 100 = 270
270 + 100 = 370

If we add 100 to 370, the number would become 470 which would be greater than 410. Now add tens to 370 until we get 410 as follows:
370 + 10 = 380
380 + 10 = 390
390 + 10 = 400
400 + 10 = 410

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Dennis_Churaev [7]

ANSWER TO QUESTION 1


f(x)=(x-2)(x+3)(x-1)^2.



EXPLANATION


The function given to us is,


f(x)=x^4-x^3-7x^2+13x-6


According to rational roots theorem,


\pm1,\pm2,\pm3,\pm6 are possible rational zeros of  


f(x)=x^4-x^3-7x^2+13x-6.


We find out that,


f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6


f(-3)=81+27-63-39-6



f(-3)=6-6



f(-3)=0


Also




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f(2)=6-6



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This implies that  


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f(x)=x^4-x^3-7x^2+13x-6 and hence (x-2)(x+3)=x^2+x-6 is also a factor.



We perform the long division as shown in the diagram.



Hence,


f(x)=(x-2)(x+3)(x-1)^2.


ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots  

x=2 and x=-3 have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.


Also the root x=1 has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.



Now we determine the position of the graph on the following intervals,


x\le -3


f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6


f(-4)=150\:>0



-3\le x \le 1


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1\le x\le 2


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x \ge 2



f(3)=24\:>0



We can now use these information to sketch the function as shown in diagram



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Step-by-step explanation:

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y = -1/2 + 13/2

y = 12/2

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