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2 years ago

Use the given information to write an equation of a line that contains a slope of 4 and passes through (-2, -6). Write your answ

er in point-slope form and slope-intercept form.

Mathematics

1 answer:

Svetach [21]2 years ago

7 0

$(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-6})\qquad \qquad \stackrel{slope}{m}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{4}(x-\stackrel{x_1}{(-2)})\implies y+6=4(x+2)$

$y+6=4x+8\implies y=4x+2\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

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Wesley wants to have at least $50 to spend each day of his 7-day vacation. He plans to save $30 each month for 12 months. Which

aleksklad [387]

Answer:

i cant choose any that applies to this question because there is no picture added to it and there are no choices to choose from. If i were to solve it though, it would be; yes, he will save enough money for his vacation.

Step-by-step explanation:

I know he would have enough--and in this case more than enough, because since he's planning to save $30 for a whole year just for $50, when he could simply make $60--which is in fact more than needed for his goal-- in just 2 months. If he were to stick with his plan though, he'd make $360. I got that by multiplying 30 by 12.

3 0

3 years ago

Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive

Nostrana [21]

Answer:

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$ = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

$\sum_{k=0}^\infty a(r)^k$

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is $\sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}$

Given series,

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

$=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......$

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

Let

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$ and $t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

Now for $S_n$ ,

$S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......$

$=\sum_{n=0}^\infty9(\frac 17)^n$

It is a geometric series.

The common ratio of $S_n$ is $\frac17$

The sum of the series

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$

$=\frac{9}{1-\frac17}$

$=\frac{9}{\frac67}$

$=\frac{9\times 7}{6}$

=10.5

Now for $t_n$

$t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......$

$=\sum_{n=0}^\infty3(\frac 15)^n$

It is a geometric series.

The common ratio of $t_n$ is $\frac15$

The sum of the series

$t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

$=\frac{3}{1-\frac15}$

$=\frac{3}{\frac45}$

$=\frac{3\times 5}{4}$

=3.75

The sum of the series is $\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

= $S_n+t_n$

=10.5+3.75

=14.25

4 0

4 years ago

Find the degree triangle

coldgirl [10]

Answer:

A) 7

Step-by-step explanation:

Because the triangles are congruent to each other, then their corresponding angles are also congruent to each other. Thus, angles Z and V are congruent to each other:

$\angle Z=\angle V\\\\40^\circ=(5n+5)^\circ\\\\35=5n\\\\7=n$