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MariettaO [177]
3 years ago
14

Suppose researchers marked 800 turtles and later were able to trap a total of 300 individuals in that population, of which 150 w

ere marked. what is the estimate for total population size
Mathematics
1 answer:
aleksklad [387]3 years ago
8 0
The estimate for the total population size is 1600.

Setting up a proportion for this, we know that 150 out of our 300 turtle sample is marked; this is the first ratio for the proportion.  We also know that we marked 800 of our total population, which we will call x:

150/300 = 800/x

Cross multiply:
150*x = 300*800
150x = 240000

Divide both sides by 150:
150x/150 = 240000/150
x = 1600
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Please help?!
Ugo [173]

draw a rectangle around it:

the widest part is from about -3 to 2 which is 5 units wide

height is from 3 to -4, which is 7 units

5*7 = 35

the top and bottom are angled so you can subtract a little for that

 so I would estimate around 32 square units

7 0
4 years ago
Read 2 more answers
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
Estela and Gavin make a poster together. Estela asks Gavin to draw a quadrilateral with a 45° angle between side lengths of 5 in
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4 0
3 years ago
Two cards are drawn with replacement, one after the other, and the outcomes recorded. What is the probability that at least one
babymother [125]

Answer:

The probability is 0.231

Step-by-step explanation:

In this question, we are tasked with calculating the probability that out of two cards drawn with replacement from a pack of cards , at least one of the two is a face card.

In a standard pack of cards, there are 52 cards.

Now let’s calculate the number of face cards we have.

There are 12 face cards in a pack of cards. There are 4 of each of Jack, Queen or King

The probability of drawing a face card is 12/52 = 3/13

Now, we want to calculate the probability of at least one of the cards drawn are face cards.

Mathematically, what we are needing to calculate is

Probability of drawing a single face card or probability of the two being a face card

Now let’s calculate.

The probability of the first card drawn being a face card is 3/13. The probability of the second card not being a face card will be 1-3/13 = 10/13

The joint probability under this first set of condition will be 3/13 * 10/13 = 30/169

Now, for the second condition, here we are considering that both cards drawn are face cards. What we have is 3/13 * 3/13 = 9/169

Now in probabilities, whenever we are having the statement or, we add the probabilities together

Thus, the probability here would be 30/169 + 9/169 = 39/169 = 3/13

In decimal this will be 0.231

8 0
3 years ago
Twice a number is 24<br>a. 2- n = 24<br>b. 2 + n = 24<br>c. 2 / n = 24 <br>d. 2n = 24​
Novosadov [1.4K]

Answer:

the answers are

a)-22

b)22

d)12

8 0
3 years ago
Read 2 more answers
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